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kiruha [24]
3 years ago
14

Electrons orbit the nucleus in specified energy

Chemistry
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

because the electron is a negatively charge and have high energy

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What are even covalent chlorides? Question D
liq [111]

Answer:

The chlorine atom (or atoms) is covalently bonded by a shared pair of electrons to the other element.

Explanation:

4 0
3 years ago
g The following reaction is the first step in the production of nitric acid from ammonia. 4NH3(g) 5O2(g) → 4NO(g) 6H2O(g) Calcul
STatiana [176]

<u>Answer:</u> The enthalpy of the reaction is coming out to be -902 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]

For the given chemical reaction:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(4\times \Delta H_f_{(NO(g))})+(6\times \Delta H_f_{(H_2O(g))})]-[(4\times \Delta H_f_{(NH_3(g))})+(5\times \Delta H_f_{(O_2)})]

We are given:

\Delta H_f_{(NO(g))}=91.3kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H_f_{(NH_3(g))}=-45.9kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(4\times (91.3))+(6\times (-241.8))]-[(4\times (-45.9))+(5\times (0))]\\\\\Delta H_{rxn}=-902kJ

Hence, the enthalpy of the reaction is coming out to be -902 kJ.

8 0
4 years ago
Why is it important for scientists to use the scientific method?
shtirl [24]
I believe the answer is A
3 0
3 years ago
Plz do 108, 110, and 112! I really need help
Gennadij [26K]
Im sorry i can only do the last one the answer might be a, d, e. Im so sorry if im wrong
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3 years ago
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What could be done to increase the acceleration of a dog sled? List two possibilities
snow_lady [41]

To increase the acceleration of the dog sled, increase the applied force on the sled and reduce the mass on the sled.

According to Newton's second law of motion, the force applied to an object is directly proportional to product of mass and acceleration of the object.

F = ma

where;

<em>a </em><em>is the </em><em>acceleration </em><em>of the dog sled</em>

a = \frac{F}{m} \\\\

To increase the acceleration of the dog sled:

  • Increase the applied force on the sled.
  • Reduce the mass on the sled.

Learn more about Newton's second law here: brainly.com/question/3999427

3 0
3 years ago
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