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lord [1]
3 years ago
12

How many carbon atoms are in 4.00g of butane

Chemistry
2 answers:
Dmitrij [34]3 years ago
5 0
1.66x10^23 atoms I hope this helps u
Svetach [21]3 years ago
5 0

Answer: 1.6221*10^23 atoms

Explanation:

Butane = C4H10

Molar mass = 58g/mol

1 mole of butane has 4 carbon atoms.

% of carbon in 1 mole of C4H10 = 4*12/58 =82.8%

Mass of carbon in 4g of butane = 82.8/100 *4 = 3.312g.

3.312g of carbon is equal to how many moles of carbon?

No.of moles = mass/ molar mass

3.312/12 = 0.276 moles.

Using Avogadro's number,

Number of atoms in any substance = Avogadro's constant * no of moles of that substance

(6.02214*10^23) * 0.276 = 1.6221*10^23 atoms.

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How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?
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Are produced 72 grams of water in this reaction.

<h3>Mole calculation</h3>

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

                          Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

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                                             74.1 = \frac{35.8}{mol}\\mol = 2

So, if there are 2 mols of Ca(OH)2:

                                  Ca(OH)2    |    H2O

                                          \frac{1mol}{2mol} =\frac{2mol}{xmol}

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Finally, just find the number of grams of water using your molar mass:

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                                              18= \frac{m}{4}\\m = 72g

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237

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