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Anton [14]
3 years ago
8

Explain how plastic can be both beneficial and detrimental at the same time.

Chemistry
1 answer:
Fofino [41]3 years ago
5 0

Answer:

Detrimental- Toxic chemicals leach out of plastic and are found in the blood and tissue of nearly all of us. Exposure to them is linked to cancers, birth defects, impaired immunity, endocrine disruption and other ailments

Beneficial- Plastic packaging helps protect and preserve goods, while reducing weight in transportation,

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What molecule is removed during dehydration synthesis?.
nignag [31]

Answer: <u> two hydrogen atoms and one oxygen</u> atom are removed during dehydration synthesis.

Hope this helps!

4 0
2 years ago
Use the above picture to fill in the blanks for the following statement. The _______sodium combines with the _______ chlorine to
zmey [24]

Your answer will be B because sodium and chlorine and both elements and two elements combine to make a compound

7 0
3 years ago
Read 2 more answers
What is the atomic number of this atom?
PIT_PIT [208]

Answer:

2?????

Explanation:

6 0
3 years ago
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Calculate the molarity of a solution with 114.95 grams of sodium dissolved in 2 L of water. ​
koban [17]

Answer:

The molarity of a solution is 2.5 M

Explanation:

Molarity is a concentration unit that describes how much of a solution is dissolved in solution.

Molarity of a solution can found by using the formula,

Molarity (M) = (moles of solute)/(Liters of Solution).

Given, mass of Sodium = 114.95 grams.

Volume of water = 2 L.

Here, Sodium is solute as it is dissolved in water, which is the solvent.

Moles of Sodium(solute) can be found by using the formula,

Number of Moles = mass/Molecular weight.

mass of Sodium = 114.95 grams.

Molecular weight = 22.989 grams

Number of Moles of Sodium(solute) =114.95/22.989 = 5.

Substituting the values in the formula, we get,

M = 5/2 = 2.5 M

3 0
3 years ago
A 10.0 mL sample of HNO3 was exactly neutralized by 13.5 mL of 1.0 M KOH. What is the molarity of the HNO3? Use the titrations f
Kruka [31]

Answer: Thus molarity of HNO_3 is 1.35 M

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=1.0M\\V_2=13.5mL

Putting values in above equation, we get:

1\times M_1\times 10.0=1\times 1.0\times 13.5\\\\M_1=1.35M

Thus molarity of HNO_3 is 1.35 M

7 0
3 years ago
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