15. 1hour 7minutes and 5seconds
The circumference when the diameter is 18 = 18pi
The circumference when the diameter is 6 = 6pi
18pi/6pi=3
The circumference will become a third of what it was.
Hope this helps!
Answer: 180 ft^3
Step-by-step explanation:
Answer:
The probability that a randomly chosen tree is greater than 140 inches is 0.0228.
Step-by-step explanation:
Given : Cherry trees in a certain orchard have heights that are normally distributed with
inches and
inches.
To find : What is the probability that a randomly chosen tree is greater than 140 inches?
Solution :
Mean -
inches
Standard deviation -
inches
The z-score formula is given by, ![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
Now,
![P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%3E%5Cfrac%7B140-%5Cmu%7D%7B%5Csigma%7D%29)
![P(X>140)=P(Z>\frac{140-112}{14})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E%5Cfrac%7B140-112%7D%7B14%7D%29)
![P(X>140)=P(Z>\frac{28}{14})](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E%5Cfrac%7B28%7D%7B14%7D%29)
![P(X>140)=P(Z>2)](https://tex.z-dn.net/?f=P%28X%3E140%29%3DP%28Z%3E2%29)
![P(X>140)=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E140%29%3D1-P%28Z%3C2%29)
The Z-score value we get is from the Z-table,
![P(X>140)=1-0.9772](https://tex.z-dn.net/?f=P%28X%3E140%29%3D1-0.9772)
![P(X>140)=0.0228](https://tex.z-dn.net/?f=P%28X%3E140%29%3D0.0228)
Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.