Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

4 0

Answer:

Use the fact that sin(x) = opp/hyp and tan(x) = opp/adj

where opp=opposite, hyp=hypotenuse, adj=adjacent and recall sin(30)=1/2 and tan(30) = 1/sqrt(3)

sin(30) = 1/2 = 17/y

y = 17(2) = 34

tan(30) = 1/sqrt(3) = 17/x

x = 17sqrt(3)

So the answer is (d)

Note that you could have also use the Pythagorean theorem to find x instead of using tan(30).

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(4x1000) + (2x100) + (3x1/10)

disa [49]

(4*1000) + (2*100) + (3*1/10) = <span>4200.3
</span>(4x1000) + (2x100) + (3x1/10) = <span>4200.3
</span>
Both are equal.

5 0

2 years ago

Read 2 more answers

Let f(x)=(8x^4-3)^3 and g(x)=8x^4-3 given that f(x)=(h g)(x) , find h(x)

Harman [31]

<u>Answer:</u>

$h(x) = x^{3}$

<u>Step-by-step explanation:</u>

$f(x) = (8 \times x^{4}- 3)^{3}$ ------------(1) (given)

$g(x) =(8 \times x^{4}- 3)$ -------------(2) (given)

so,

f(x) = h(g(x)) (given)

= $(g(x))^{3}$ -----(from (1) and (2))

⇒ $h(k) = k^{3}$ -----(taking g(x) = k)

⇒ $h(x) = x^{3}$ is the function.

8 0

3 years ago

Someone help me please and thank you!! ASAP :(

pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$