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OlgaM077 [116]
2 years ago
10

The square root of 105 would lie between which two consecutive integers?

Mathematics
1 answer:
12345 [234]2 years ago
8 0

Answer:

the square root of 105 lies between 10 and 11

Step-by-step explanation:

Which perfect squares "box" 105 in?  10^2 = 100 and 11^2 = 121.

The square roots of 100 and 121 are 10 and 11.  

Thus, the square root of 105 lies between 10 and 11.

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Step-by-step explanation:

Do you mean f(x)=2sin(x-1) or f(x)=2sin(x) -1?

Use the formula f(x)=asin(bx+c)+d where |a| is the amplitude, -\frac{c}{b} is the phase shift, d is the vertical shift, and the period is \frac{2\pi}{|b|}.

Assuming your first case is true, the amplitude would be |a|=|2|=2, your period is \frac{2\pi}{|1|}=2\pi, and your midline/vertical shift is d=0.

Assuming your second case is true, everything but the vertical shift stays the same. It would be d=-1 in this case.

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The two numbers are 31 and 35.

Step-by-step explanation:

Let,

one number = x

2nd number = y

According to statement;

x+y=66   Eqn 1

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Putting y=x+4 from Eqn 2 in Eqn 1;

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The two numbers are 31 and 35.

Keywords: Linear equation, Addition

Learn more about linear equations at:

  • brainly.com/question/9862781
  • brainly.com/question/9762331

#LearnwithBrainly

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Step-by-step explanation:

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