Answer:
7.09 mph
30.87 mph
Step-by-step explanation:
We are given that
![\theta=77^{\circ} 48'=77+\frac{48}{60}=77.8^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D77%5E%7B%5Ccirc%7D%2048%27%3D77%2B%5Cfrac%7B48%7D%7B60%7D%3D77.8%5E%7B%5Ccirc%7D)
1 degree=60 minute
The speed of boat in still water=v=31.7mph
We have to find the speed of the current and the actual speed of the motorboat.
![\theta'=90-77.8=`2.92^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%27%3D90-77.8%3D%602.92%5E%7B%5Ccirc%7D)
Speed of the current=![vsin\theta'](https://tex.z-dn.net/?f=vsin%5Ctheta%27)
Speed of the current=![31.7sin12.92=7.09 mph](https://tex.z-dn.net/?f=31.7sin12.92%3D7.09%20mph)
Actual speed of the motorboat=![vcos\theta'=31.7cos12.92=30.87mph](https://tex.z-dn.net/?f=vcos%5Ctheta%27%3D31.7cos12.92%3D30.87mph)
Answer:
y=28
Step-by-step explanation:
6x-y=2
-y=2-6x
y=6x-2
4x-(6x-2)=-8
4x-6x+2=-8
-2x=-10
x=5
y=6*5-2=30-2=28
y=28
I’m pretty sure that last one is write
Answer:
(6,0)
(-2,0)
2,-3
-3,-2
7,7
Step-by-step explanation:
Answer:
22.34
Step-by-step explanation: