Answer:
Step-by-step explanation:
x![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx)
XE[_4.2,2.2]
3/3=1 and 7/8 is < 1 so 3/3 is bigger
The point of intersection of both graphs will have the coordinate (5, 9).
<h3>What is the Point of Intersection of the Graph?</h3>
We are given the functions;
f(x) = x + 4
g(x) = -2x + 19
Now, the point of intersection of both graphs is when both functions are equal which is at f(x) = g(x). Thus;
x + 4 = -2x + 19
x + 2x = 19 - 4
3x = 15
x = 15/3
x = 5
Thus;
f(x) = 5 + 4 = 9
g(x) = -2(5) + 19 = 9
Thus, the point of intersection of both graphs will have the coordinate (5, 9)
Read more about Graph Intersection at; brainly.com/question/11337174
#SPJ1
Point S makes the two connected angles the same. They both have right angles.
And one side of each is congruent.
This means you know 2 angles are the same and one side is the same.
You would use ASA (Angle, Side, Angle)
