Formula of the sum of the 1st nth term in a Geometric Progression:
Sum = a₁(1-rⁿ)/(1-r), where a₁ = 1st term, r = common ratio and n= rank nth of term (r≠1)
Sum = (-11)[1-(-5⁸)] /[(1-(-5)]
Sum = (-11)(1- 390625)/(6)
SUM = 716,144
Answer:
6, 11, 16, 21
Step-by-step explanation:
To obtain the first 4 terms add the common difference 5 to the previous term, that is
a₁ = 6
a₂ = a₁ + 5 = 6 + 5 = 11
a₃ = a₂ + 5 = 11 + 5 = 16
a₄ = a₃ + 5 = 16 + 5 = 21
Answer:
=
−
0
.
8
Step-by-step explanation:
The answer is : y=-6-47
:)
Company C services 16 office suites.
Company A services 1/3 of the suites and Company B services 2/5; together they service 1/3+2/5. Find a common denominator; 15 is the smallest:
1/3=5/15
2/5=6/15
5/15+6/15 = 11/15
This means that 1-11/15 = 4/15 of the suites are serviced by Company C.
4/15 of 60 = 4/15(60) = 4/15(60/1) = 240/15 = 16