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pshichka [43]
3 years ago
5

What is the median price of rent for the university of oregon

Mathematics
1 answer:
almond37 [142]3 years ago
5 0

Answer:

$11,450

Step-by-step explanation:

thats the median price according to Google

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Write 0.1 as a fraction in simpliest form
lakkis [162]

Answer:

the answer is 1/10.....and yh

7 0
3 years ago
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Estimate by rounding each number to the nearest hundredth and then subtract 360.727 - 89.852
kykrilka [37]
Hi there!

The correct answer for you is 270.88.

To round to the hundreth's place (.0<u>1</u><u />), you need to take the number in the thousand's place (.00<u>1</u>), and determine if the number needs to go up or down.

If the number in the thousand's place is <u>greater</u> than 4, then the number goes up.

360.72<u>7</u> --> This means that the hundreth's number goes up to 3.

If the number in the thousand's place is <u>lesser</u> than 5, then that number stays the same.

89.85<u>2</u> --> This means that the hundreth's number stays the same.

After you round, then just subtract:

360.73 - 89.85 = 270.88.

I hope this helps!
Brady
<u />

7 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
2 years ago
Y is directly related to X, and Yis 81 when X is 27.<br> The constant of variation is
Arisa [49]

Answer:

3

Step-by-step explanation:

A direct variation is of the form

y = kx

We know x and y so we can find k

81 = k *27

Divide each side by 27

81/27 = 27k/27

3=k

The constant of variation is 3

5 0
3 years ago
A fraction with a numerator of 1 is called a _ fraction
Oksi-84 [34.3K]

Answer:

Unit fraction

Step-by-step explanation:

A unit fraction means 1 unit is the value of the numerator. This means 1 is in the numerator.

8 0
2 years ago
Read 2 more answers
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