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3 years ago

Find Mn to the nearest tenth

Mathematics

1 answer:

krok68 [10]3 years ago

4 0

Answer:

B. 23.8

Step-by-step explanation:

Use the formula c = \sqrt a^2+b^2﹣2abcosy (squareroot the whole thing)

c = length of side you are finding

a = length of side a

b = length of side b

y =angle opposite c

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Which statement is always false?

FinnZ [79.3K]

Answer:

All parallelograms are squares

Step-by-step explanation:

Reasoning:

You can have a parallelogram with side lengths, i dont know, 5 and 3, right? That isn't a square :)

8 0

3 years ago

For an investment of $26,245, a quarterly statement reports that the account balance is $26,292. The statement also reports that

Paul [167]

No, it does not seem reasonable. The quarterly statement reports an increase of $47, so it would be a positive rate of return on the investment instead of a negative rate.

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4 years ago

50 is 40% of what number??????

kvv77 [185]

So a hack is we know that 20% times 5 =100% and 40 divided by 2=20 so

50=40%
divide both sides by 2
25=20%

20 times 5=100 so
multiply both sides by 5
125=100%

8 0

4 years ago

Read 2 more answers

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

4 years ago

Read 2 more answers

What is the volume of this sphere <br> Use π=3.14 and round your answer to the nearest hundredth

Alina [70]

The answer is 523.6 and all you have to do is round it to the nearest hundredth

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3 years ago