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schepotkina [342]
3 years ago
14

What fraction of all the 10-digit numbers with distinct digits have the property that the sum of every pair of neighboring digit

s is odd?
Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

1/126

Step-by-step explanation:

Answer attached, I hope this is the answer.

the sum of every pair of neighboring digits is odd must be odd number and even number in the neighbor. (different parity)

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If two polygons are SIMILAR, then the corresponding sides must be and the corresponding angles must be .
AveGali [126]

Answer:

Their sides must be in the same ratio and their angles must be equal.

Step-by-step explanation:

If two polygons are similar their sides must be in the same ratio and their angles must be equal.

e. g. -

If ABCDEF  and GHIJKL be the two polygons,

then,

\frac{AB}{GH} = \frac{BC}{HI} = \frac{CD}{IJ} = \frac {DE}{JK} = \frac {EF}{KL} = \frac{FA}{LG}

and,

∠ABC = ∠GHI ; ∠BCD =∠HIJ ; ∠CDE = ∠IJK ; ∠DEF =∠JKL ; ∠EFA =∠KLG;

∠FAB = ∠LGH .

5 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
3 years ago
Perform the indicated operation.(4r/r+3) - (5/r)
Aleks [24]

Answer:

4r² - 5r - 15 / r(r+3)

Step-by-step explanation:

To solve this problem, we will proceed the following way, writing down the common multiple of the denominators.

\frac{4r}{r+3} -\frac{5}{r} =\frac{4r(r)-5(r+3)}{r(r+3)} =\frac{4r^{2}-5r-15 }{r(r+3)}

Thus, the answer is 4r² - 5r - 15 / r(r+3)

7 0
4 years ago
This month carla caught the following fish in lake george<br><br><br> will mark brainliest
Ira Lisetskai [31]

Answer:

The fish could be a seafish.

Step-by-step explanation:

Seafishes are fishes that live in the sea most of the time.

5 0
3 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
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