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IgorLugansk [536]

3 years ago

9

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units. What is BC, the height of th

e pyramid? 7 units 7StartRoot 2 EndRoot units 14 units 14StartRoot 2 EndRoot units

2 answers:

loris [4]3 years ago

6 0

Answer:

c

Step-by-step explanation:

took test

AlladinOne [14]3 years ago

5 0

Answer:

It's not B

Step-by-step explanation:

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You are hosting a convention for a charitable organization. You pay a rental fee of $28,500 for the convention center, plus you

Alexxandr [17]

You have to add the $51 to $13 and find the answer then divide the sum by $28,500

8 0

3 years ago

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What is the solution to the equation<br> 3x+9-7x=2(x+6)

Tasya [4]

Answer:

x=-1

Step-by-step explanation:

hello :

3x+9-7x=2(x+6)

3x+9-7x=2x+12

3x-2x-7x=12-9

-6x = 6

x=6/-6 = -1

5 0

3 years ago

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The sum of the squares of 2 consecutive negative integers is 41. What are the numbers? Which of the following equations is the r

VARVARA [1.3K]

Answer:
The two numbers are -5 and -4

Explanation:
Assume that the first number is x and that the second number is x+1.
We know that the sum of their squares is 41. This means that:
x² + (x+1)² = 41

We will expand the brackets and factorize to get the value of x as follows:
x² + (x+1)² = 41
x² + x² + 2x + 1 = 41
2x² + 2x + 1 - 41 = 0
2x² + 2x - 40 = 0
We can divide all terms by 2 to simplify the equation:
x² + x - 20 = 0 ..........> equation required in part II

Now, we can factorize this equation to get the values of x:
x² + x - 20 = 0
(x-4)(x+5) = 0
either x = 4 .........> rejected because we know that x should be negative
or x = -5 ...........> accepted

Based on the above calculations, the two numbers are -5 and -4

Hope this helps :)

8 0

4 years ago

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Find the lengjth of the missing figure.<br>x=__cm

miv72 [106K]

Answer:

X = 16 cm

Step-by-step explanation:

Pythagoras law is :

20^2 = X^2 + 12^2

400 = X^2 +144

400 - 144 = x^2

256 = x^2

x = ( 256 ) ^1/2

X=16

3 0

3 years ago

Write the quadratic function y = x2 + ax (assuming a is nonzero) in vertex form.

konstantin123 [22]

Get into form y=a(x-h)²+k where (h,k) is vertex

some terms:
quadratic coefient: number in front of the x² term
linear coefient: number in front of the x term

basically complete the square
so
y=x²+ax
first factor out the quadratic coefient (1),
y=1(x²+ax)
take 1/2 of the linear coefient and square it
$\frac{a}{2}=\frac{a}{2}$ , $(\frac{a}{2})^2=\frac{a^2}{4}$
add positive and negative of it inside the parentesees
$y=1(x^2+ax+\frac{a^2}{4}-\frac{a^2}{4})$
factor perfect square
$y=1((x+\frac{a}{2})^2-\frac{a^2}{4})$
distribute
$y=1(x+\frac{a}{2})^2-\frac{a^2}{4}$

so invertex form, it is
$y=1(x+\frac{a}{2})^2-\frac{a^2}{4}$ or
the vertex is $(\frac{-a}{2},\frac{-a^2}{4})$

4 0

4 years ago