<span>When creating a subset of 5 elements from 7 elements, order should not matter. Therefore, we use the combination formula over the permutation formula.
The combination formula given n elements total and r elements used is n! / [r!*(n-r)!]. Substituting 7 for n and 5 for r, we get:
7! / (5!*2!) = 7*6 / 2 = 21
21 subsets can be created</span>
Answer:
x
5
Step-by-step explanation:
First choose a variable to represent the number,
Let's call it
x
We need to divide that number by
5
x
÷
5
or
x
5
is how you write it as an expression.
The answer i think is. If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
The exact form is: w = -6/7