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rjkz [21]
3 years ago
14

Lucas took his bike to a local park to ride on some bike trail.Trail A is 6 3/4 miles long.Trail B is 8 1/2 miles long. How many

miles long is Trail B then Trail A
Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer: Trial B is 1\dfrac{3}{4} miles longer then Trail A.

Step-by-step explanation:

Length of Trail A = 6\dfrac34 miles

= \dfrac{24+3}{4}  miles = \dfrac{27}{4} miles.

Length of Trail B = 8\dfrac12 miles

= \dfrac{16+1}{2} miles = \dfrac{17}{2} miles.

Trial B is longer then Trail A by \dfrac{17}{2}-\dfrac{27}{4} miles

=\dfrac{17\times2}{2\times2}-\dfrac{27}{4} miles

=\dfrac{34}{4}-\dfrac{27}{4} miles

=\dfrac{7}{4} miles

=1\dfrac{3}{4} miles

Hence, Trial B is 1\dfrac{3}{4} miles longer then Trail A.

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3 years ago
Approximate the zeros of the function. Round to the nearest tenth if necessary. f(x) = 4x^2 + 4x - 35. Explain each step on how
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4x²+4x-35=0
factor: (2x+7)(2x-5)=0
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I don't see any rounding necessary in this case. 

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
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8 0
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Determine which equation is parallel to the line JK and which is perpendicular to like JK
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Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and y = - \frac{1}{m}x + b will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as  

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