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Nastasia [14]
3 years ago
15

How many bags of fertilizer are needed to fertilize a yard measuring 60 feet by 80 feet if one bag will cover 100 square feet

Mathematics
1 answer:
notka56 [123]3 years ago
3 0
The yard is 60ft * 80ft = 4800ft2.

One bag covers 100ft2.

4800ft2/100ft2/bag = 48 bags
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100÷11=9.09090909
converting it it will be 9.1 miles per hour
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3 years ago
I need help with this question?????
tangare [24]
Its just multiplied by 2
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3 years ago
Read 2 more answers
Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!
ra1l [238]

Answer:

a

Step-by-step explanation:

6 0
2 years ago
A 20-gallon salt-water solution contains 15% pure salt. How much pure water should be added to it to produce a 10% solution?
Elanso [62]

15% of 20 gal = 0.15 * 20 gal = 3 gal, so the solution contains 3 gal of salt.

If we add <em>x</em> gal of water to the solution, we end up with (20 + <em>x</em>) gal of solution. We want the new mixture to have a concentration of 10%, or

10% of (20 + <em>x</em>) gal = 0.1 * (20 + <em>x</em>) gal = 2 + 0.1<em>x</em> gal

of salt.

The amount of salt in the tank hasn't changed. Solve for <em>x </em>:

2 + 0.1<em>x</em> = 3

0.1<em>x</em> = 1

<em>x</em> = 10 gal

3 0
3 years ago
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