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oksano4ka [1.4K]
2 years ago
9

Circles multiple choicegeometry please help​

Mathematics
1 answer:
Alexxx [7]2 years ago
5 0

Answer:

a) 12 ( I'm pretty sure)

Step-by-step explanation:

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Answer please and thank you
Luba_88 [7]
1/8 is the answer hope this helped
5 0
3 years ago
In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0
3 years ago
Can somebody please help me with this
pickupchik [31]

Answer:

13.35

Step-by-step explanation:

you multiply 89 times 15

then divide that with 100

6 0
3 years ago
Using place value how to increase 2384598 by six million
Leno4ka [110]
6 million = 6,000,000

2,384,598 + 6,000,000 = 8,384,598

your answer is 8,384,598

hope this helps
3 0
3 years ago
Can someone help and give me a step by step explanation please?!
vitfil [10]

9514 1404 393

Answer:

  • ∠QSR = 78°
  • ∠SQR = 51°

Step-by-step explanation:

The measure of an inscribed angle (QTR) is half the measure of the arc it intercepts. The measure of an arc is the same as the measure of the central angle it intercepts. So, we have ...

  ∠QSR = 2×∠QTR

  ∠QSR = 2×39°

  ∠QSR = 78°

__

Sides SQ and SR are radii of circle S, so are the same length. That means triangle QRS is an isosceles triangle and the base angles SQR and SRQ are congruent. The sum of angles in a triangle is 180°, so we have ...

  ∠QSR + 2(∠SQR) = 180°

  78° + 2(∠SQR) = 180° . . . . fill in the value we know

  2(∠SQR) = 102° . . . . . . . . . subtract 78°

  ∠SQR = 51° . . . . . . . . . . . . .divide by 2

7 0
2 years ago
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