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Darina [25.2K]
3 years ago
14

A car that travels 20 miles in LaTeX: \frac{1}{2}1 2 hour at constant speed is traveling at the same speed as a car that travels

30 miles in LaTeX: \frac{3}{4}3 4 hour at a constant speed. Both cars go miles in LaTeX: \frac{1}{4}1 4of an hour (or 15 minutes). Both cars will travel miles in 1 hour.
Mathematics
1 answer:
charle [14.2K]3 years ago
5 0

Answer:

10 miles per 1/4 hour

40 miles per hour

Step-by-step explanation:

Given that:

A car travels 20 miles in 1/2 hour

Miles traveled per hour :

(20 * 2) / 1 = 40 miles per hour

Mile traveled in 1/4 hour :

Distance = speed * time

Distance = 40 mph * 1/4 = 10 miles per 1/4 hour

Car traveling 30 miles in 3/4 hours

(30 * 4) /3 = 120 / 3 = 40 miles per hour

Distance = 40 mph * 1/4 = 10 miles per 1/4 hour

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Find the 7th term of the geometric sequence a3 =128,r=-1/4
kenny6666 [7]

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1).  We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

or

a(7) = 8(-1/4)^7

7 0
3 years ago
What is 44.6825 rounded to the nearest hundredth
iren [92.7K]

Answer:

44.68

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

44.6825 rounded to the nearest hundredths place is 44.68

(っ◔◡◔)っ ♥ Hope this helped, have a great day! ♥

˜”*°•.˜”*°• ~Star •°*”˜.•°*”˜

5 0
3 years ago
The measure of angle S is 65 degrees.
suter [353]

Answer:

A. 115°

Step-by-step explanation:

180° - 65° = 115°

5 0
3 years ago
498,147,846,267<br>+ 32,870,714,538<br>​
san4es73 [151]

Answer:

531018560805

Step-by-step explanation:

4 0
2 years ago
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
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