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KatRina [158]
3 years ago
12

Write an explicit formula for an, then th term of the sequence 75, 15, 3, ..

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

This isn't the full question cause this just doesn't make sense.

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The graph of a quadratic function intercepts the x-axis in two places and the y-axis in one place.
LiRa [457]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
There are square tiles arranged in a pattern. the pattern has rows that are 5 tiles wide and an unknown number of rows. if you t
KonstantinChe [14]

An equation is formed of two equal expressions. The number of rows in the original pattern will be 4.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the number of rows be represented by x. Now, the pattern has rows that are 5 tiles wide and an unknown number of rows. if you take these tiles and add one additional tile, you can create a pattern that has rows that are 3 tiles wide, with 3 more total rows than the original pattern. Therefore, we can write,

(Number of Tiles before) + 1 tile = (Number of Tiles afterward)

5x + 1 = 3(x+3)

5x + 1 = 3x + 9

5x - 3x = 9 - 1

2x = 8

x = 4

Hence, the number of rows in the original pattern will be 4.

Learn more about Equation:

brainly.com/question/2263981

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5 0
2 years ago
I need answers ASAP please algebra homework
Ipatiy [6.2K]
A. (2,0) (0,-3)
B. slope= 3/2
C. y= 3/2x-3
D. 3/2x+y= -3
8 0
3 years ago
Need help with this<br>​
AleksandrR [38]

Step-by-step explanation:

\cos( \beta  )  +  \sin( \beta )  \tan( \beta )  =  \sec( \beta )

\cos( \beta )  +  \sin( \beta )  \frac{ \sin( \beta ) }{ \cos( \beta ) }

\cos( \beta )  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{ \cos {}^{2} ( \beta ) }{cos \beta }  +  \frac{ \sin {}^{2} ( \beta ) }{ \cos( \beta ) }

\frac{1}{ \cos( \beta ) }

=  \sec( \beta )

3 0
3 years ago
Read 2 more answers
What is the equation of the line that contains the point (-1, 4) and has a slope of 3?
sertanlavr [38]

Let's write the equation with formula:-

\boxed{ \sf \: formula : y -y_{1} =  m(x -  x_{1})}

Where,

  • x1 is -1 and y1 is 4 and m is 3

\tt \: y - 4= 3(x - ( - 1))

\tt \: y  - 4 = 3(x + 1)

\tt \: y  - 4 = 3x + 3

\tt \: y = 3x + 3 + 4

\tt \: y = 3x + 7

<em>Thus, The correct choice is option C!!~</em>

4 0
2 years ago
Read 2 more answers
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