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3 years ago

Please help ASAP only if you know the answer or I will report

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

D) 7, 24, 27 is NOT a right triangle

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A square shaped patio has an area of 256 ft 2 what are the dimensions of the patio

Romashka-Z-Leto [24]

Step-by-step explanation:

√256

it's a 16in x16in patio

all four sides are 16

3 0

3 years ago

HELP PLEASE Rory has 10 Gallons 8 cups of water to fill her aquarium how many cups of water does she have? Hint: 1 gallon = 16 c

Lesechka [4]

Answer:

Rory has 168 cups of water

Step-by-step explanation:

Since 1 Gallon is equals to 1 cups, multiply it by 10 gallons then add 8 cups to it

Hope this helps

4 0

3 years ago

Read 2 more answers

HELP I CANT DO THIS-

Vera_Pavlovna [14]

1. C. Rectangle
2. F. 160
3. D. Triangular prism
4. H. 30 boxes
5. C. Equilateral Triangle

3 0

3 years ago

Find the value of y in the formula y=5a-3b c, if a=12,b=4,c=8

liberstina [14]

Y=5a-3b
Y=5(12)-3(4)
Y=60-12
Y=48

You don't have a sign between b and c in the equation, so I cannot help you with the last operation

8 0

3 years ago

Read 2 more answers

Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul

natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

$\bf B=\displaystyle\frac{L}{4\pi d^2}$

where

L = luminosity of the star (related to the Sun)

d = distance in ly (light-years)

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of Alpha Centauri A is

$\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728$

According to the inverse square law for light intensity

$\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}$

where

$\bf I_1=$ light intensity at distance $\bf d_1$

$\bf I_2=$ light intensity at distance $\bf d_2$

Let $\bf d_2$ be the distance we would have to place the 50-watt bulb, then replacing in the formula

$\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}$

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0

3 years ago