Answer:
86
Step-by-step explanation:
![48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2{1 (2 - 15÷3)}] \\ 8[ - 2.5{ (2 - 15÷3)}] \\ 8[ - 2.5{ ( - 13÷3)}] \\ 8[ - 2.5{ ( - 4.3)}] \\ 8[10.75 { }] \\ = 86](https://tex.z-dn.net/?f=48%C3%B76%20%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%7B1%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20-%2013%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20%20-%204.3%29%7D%5D%20%5C%5C%208%5B10.75%20%7B%20%7D%5D%20%5C%5C%20%20%3D%2086)
Solve first equation for y:
5x+y=10
y=10-5x. Plug this equation into second equation
-x-(10-5x)=-2
-x-10+5x=-2
4x=8
x=2 (plug x into first equation)
5(2)+y=10
y=0
Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
The second step is to keep your x terms on the left and move the constant to the right by subtracting it from both sides.
Answer:
There can be infinite possibilities as long as the slope is the same (1/3)
Step-by-step explanation:
For example; y=1/3x+5(+/-)