Answer: Partial pressure of
at a depth of 132 ft below sea level is 2964 mm Hg.
Explanation:
It is known that 1 atm = 760 mm Hg.
Also, ![P_{N_{2}} = x_{N_{2}}P](https://tex.z-dn.net/?f=P_%7BN_%7B2%7D%7D%20%3D%20x_%7BN_%7B2%7D%7DP)
where,
= partial pressure of ![N_{2}](https://tex.z-dn.net/?f=N_%7B2%7D)
P = atmospheric pressure
= mole fraction of ![N_{2}](https://tex.z-dn.net/?f=N_%7B2%7D)
Putting the given values into the above formula as follows.
![P_{N_{2}} = x_{N_{2}}P](https://tex.z-dn.net/?f=P_%7BN_%7B2%7D%7D%20%3D%20x_%7BN_%7B2%7D%7DP)
![593 mm Hg = x_{N_{2}} \times 760 mm Hg](https://tex.z-dn.net/?f=593%20mm%20Hg%20%3D%20x_%7BN_%7B2%7D%7D%20%5Ctimes%20760%20mm%20Hg)
= 0.780
Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of
is as follows.
![P_{N_{2}} = x_{N_{2}}P](https://tex.z-dn.net/?f=P_%7BN_%7B2%7D%7D%20%3D%20x_%7BN_%7B2%7D%7DP)
= ![0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}](https://tex.z-dn.net/?f=0.78%20%5Ctimes%205%20atm%20%5Ctimes%20%5Cfrac%7B760%20mm%20Hg%7D%7B1%20atm%7D)
= 2964 mm Hg
Therefore, we can conclude that partial pressure of
at a depth of 132 ft below sea level is 2964 mm Hg.
Answer: The answer can be found on CHEG
Explanation:
Https://chem.libretexts.org/Core/Analytical_Chemistry/Quantifying_Nature/Units_of_Measure/SI_Units
Look for it here