<span>According to the question-
1 mol C3H8O = 60.096 g C3H8O
2 mol C3H8O = 9 mol O2
1 mol O2 = 31.998 g O2
[(3.00 g C3H8O)/1][(1 mol C3H8O)/(60.096)][(9 mol O2)/(2 mol C3H8O)][(32.998 g O2)/(1 mol O2)] = 7.1880435 g O2
Since 7.1880435 g of O2 is needed, and 7.38 g of O2 is available, 0.199565 g of O2 will be left over and oxygen is present in excess.
Next, we need to convert 0.199565 g of O2 into moles of O2:
[(0.199565 g O2)/1][(1 mol O2)/(31.998 g O2)] = 0.005999 mol O2, or 0.006 mol O2</span>
Answer:
The NH3 + with a PKa = 9.9
Explanation:
The Pka is a mathematical expression to express the dissociation grade of a substance in a solution, that means with a substance with a pKa small is a strong acid, and in this case since the solution pH is 8, that mean that the substance with high pKa ( lower acid strength) will predominate in a pH of 8.
Hey there!
We balance chemical equations because of the law of conservation of mass.
The law of conservation of mass states that matter cannot be created or destroyed, so we must have the same amount of each element on each side of a chemical equation.
The products of a chemical reaction must be equal to the reactants to follow the law of conservation of mass.
Hope this helps!
When the balanced equation for this reaction is:
2SO3 → 2SO2 + O2 so, by using ICE table:
initial 0.391 0 0.125m
change -X +2X +X
Equ (0.391-X) 2X 0.125+X
when Keq = concentration of products / concentration of reactants
so, by substitution
4.34 = [2X]^2 * [0.125+X] / [0.391-X]^2 by solving for X
∴ X = 0.357 m
∴ the concentration of SO2 = 2x = 2 * 0.357
= 0.714 m
