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krek1111 [17]
3 years ago
11

What is the amount of matter in an object. A mass B volume C Density

Chemistry
2 answers:
Sever21 [200]3 years ago
7 0
Mass mass mass mass mass mass
Jobisdone [24]3 years ago
3 0

Answer:

Option A

Explanation:

The answer is "mass" or option A. It's not option B because volume is the amount of space in a object which is not what the question is asking for. It's also not option C because density goes hand in hand with volume measuring how much space a object takes up, and also density is mass per volume. Leaving only option A, therefore it is your answer.

Hope this helps.

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I believe the correct answer from the choices listed above is option A. To correct her measurement to standard temperature and pressure (STP), she should <span>make a volume correction based on a higher temperature of 273 K. Hope this answers the question. Have a nice day.</span>
8 0
3 years ago
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How many formula units are contained in 23.5 g of Sb2S3
wolverine [178]
The molar mass of Sb2S3 is approximately equal to 339.7 g/mol. We calculate the number of moles of Sb2S3 by dividing the given mass by the molar mass. 
                                     n = 23.5 g / (339.7 g/mol)
                                        n = 0.0692 mols
To calculate for the number of formula units, we multiply the number of mols by the Avogadro's number, 
                            number of formula units = (0.0692 mols)(6.022 x 10^3)
                                                   = 4.167 x 10^22 formula units
7 0
3 years ago
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The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
What would barium do to obtain a noble gas structure? gain 2 electrons lose 2 electrons gain 6 electrons lose 6 electrons
Tema [17]

Answer:

Lose two electrons.

Explanation:

Barium is present in group 2.

It is alkaline earth metal.

Its atomic number is 56.

Its electronic configuration is Ba₅₆ = [Xe] 6s².

In order to attain the noble gas electronic configuration it must loses its two valance electrons.

When barium loses it two electron its electronic configuration will equal to the Xenon.

The atomic number of xenon is 54 so barium must loses two electrons to becomes equal to the xenon.

4 0
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A scientist exam in two atoms. One has a nucleus with five protons in five neutron surrounded by five electrons. The other has a
grigory [225]

Answer:

C) They are not made of matter.

Explanation:

Case in which protons are inside of neutrons doesn't exist.

8 0
3 years ago
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