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klio [65]
3 years ago
8

Electrical charge may be rapidly moved from one body to another by means of a(n)

Chemistry
2 answers:
Snowcat [4.5K]3 years ago
5 0
<span>Conductor, and there you go, i hope this helped but if its wrong, i am extremly sorry</span>
True [87]3 years ago
5 0
The answer for the problem would be called a conductor.

Hope this helps!<span />
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ASPA!!!! How could a scientist determine what elements are present in a distant star by looking at its absorption spectrum?
8_murik_8 [283]

Answer:

Spectroscopy

Explanation:

They can determine its composition based on these wavelengths. The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy

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2 years ago
What is the name of the ionic compound Csmc010-1.jpgS? cesium sulfur cesium sulfide dicesium sulfur dicesium sulfide
nika2105 [10]
Answer is: cesium sulfide.
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3 years ago
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Assignment Directions: Pick one of the following chemists and perform a bit of research on him/her. Answer the following questio
avanturin [10]
Don’t worry about it, let me do your homework!

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8 0
3 years ago
Which of the following are diatomic elements? CHECK ALL THAT APPLY!
Komok [63]

Answer: This is a list of the seven diatomic elements. The seven diatomic elements are:

   Hydrogen (H2)

   Nitrogen (N2)

   Oxygen (O2)

   Fluorine (F2)

   Chlorine (Cl2)

   Iodine (I2)

   Bromine (Br2)

All of these elements are nonmetals, since the halogens are a special type of nonmetallic element. Bromine is a liquid at room temperature, while the other elements all gases under ordinary conditions. As the temperature is lowered or pressure is increased, the other elements become diatomic liquids.

Astatine (atomic number 85, symbol At) and tennessine (atomic number 117, symbol Ts) are also in the halogen group and may form diatomic molecules. However, some scientists predict tennessine may behave more like a noble gas.

While only these seven elements routinely form diatomic molecules, other elements can form them. However, diatomic molecules formed by other elements are not very stable, so their bonds are easily broken.

How to Remember the Diatomic Elements

The elements ending with "-gen" including halogens form diatomic molecules. An easy-to-remember mnemonic for the diatomic elements is: Have No Fear Of Ice Cold Beer

Explanation:

SORRY if you don't understand!

6 0
2 years ago
Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a
horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound            Amount

     Ni                        12.7 g

   CO                        1.98 g

Ni(CO)_4                  0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of Ni(CO)_4 = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M

\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M

\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M

For the given chemical reaction:

Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)

The expression of equilibrium constant for the reaction:

K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0
3 years ago
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