Answer:
(a) Orthogonal, (b) Neither, (c) Parallel, d( Orthogonal
Step-by-step explanation:
a and b are parallel is a=kb
a and b if a dot b = 0
(a) a dot b = (9)(-4)+6(6)=-36+36=0
a and b are orthogonal
(b) a dot b = 40-7-21=12
a=kb -> there is no k value satisfying the equation
a and b are neither parallel or orthogonal
(c) a dot b = -12-108-48=-168
a=kb -> k=-3/4 satisfies the equation
a and b are parallel
(d) a dot b= 9-3-6=0
a and b are orthogonal
Answer:
a) -27 a³ b⁶
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given ( -3 ab² )³
By using (ab )ⁿ = aⁿ bⁿ
( -3 ab² )³ = (-3)³ a³ (b²)³
Again , using formula 
= -27 a³ b⁶
There would be 8 whole(s) in total.
It would be B. 5cm 12cm and 13cm
Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
