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Margaret [11]
3 years ago
6

Find the term that must be added to the equation x^2−6x=7 to make it into a perfect square.

Mathematics
1 answer:
lora16 [44]3 years ago
7 0
The wander is C, -7
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2 years ago
16^5/4•16^1/4/(16^1/2)^2
Kazeer [188]

Answer:

The simplified expression is 16^-1/6

Step-by-step explanation:.

16^5/4•16^1 /4/ (16^1/2)^2

The dot means multiplication. The expression is rewritten as

16^5/4 × 16^1/4 / (16^1/2)^2

Recall the following rules of indices

1) y^a × y^b = y^(a+b)

2) (y^a)^b = y^ab

y^b/ y^a = y^(b-a)

Applying these rules of indices

16^5/4 × 16^1/4= 16^((5/4×1/4) = 16^((5/16)

(16^1/2)^2= 16^ 1/2×2 = 16^1 = 16

Therefore

16^5/4 × 16^1/4 / (16^1/2)^2

= 16^(5/16) /16

=16^(5/6) × 16^-1

= 16^ (5/6)-1

= 16^-1/6)

,The simplified expression is 16^-1/6

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3 years ago
Evaluate u+ xy for u=9, x=9, y=7
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U+xy
On replacing for u, x and y.
=9+9*7
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=72

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3 years ago
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