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REY [17]
3 years ago
12

4

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

x = 5,24

Step-by-step explanation:

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Find the solution of this system of equations. Separate the x- and y-values with a comma. x = 8 + y and x - 11y = -12
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The answer is:
(10, 2)
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3 years ago
2. Write the slope-intercept form of the equation for each graph described. Line passing through (-5, 12) and parallel to the li
Nostrana [21]

Answer:   y = 2x+22

========================================================

Explanation:

The equation y = 2x+5 is in the form y = mx+b

m = 2 = slope

b = 5 = y intercept

Parallel lines have equal slopes, but different y intercepts. So the answer will be in the form y = 2x+c, where b and c are different numbers. Since b = 5, this means c must be some other number. If c = 5, then we'd have the exact same line.

Let's plug in (x,y) = (-5,12), along with the slope m = 2, and solve for c

y = mx+c

12 = 2(-5)+c

12 = -10+c

12+10 = c

22 = c

c = 22

Since m = 2 and c = 22, we go from y = mx+c to y = 2x+22

The equation of the parallel line is y = 2x+22

The graph is below.

7 0
3 years ago
1)
Ostrovityanka [42]
◆ Straight Lines ◆

Heya !

1) \: line \: is \: passing \: through \:points \: (5,7) \: and \: (6,8) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: = \: \frac{(8 - 7)}{(6 - 5)} = \: 1 \\ \\ equation \: of \: line \: = \: (y - y1) \: = m (x - x1) \\ \\ equation \: of \: line \: =( y - 7) = 1(x - 5) \\ \\ equation \: of \: line \: - \\ x - y + 2 = 0 \: ans. \\ \\ \\ 2) \: line \: is \: passing \: through \: ( - 3,6) \: and \: ( 3, - 6) \\ \\ slope \: of \: line \: = \frac{(y2 - y1)}{(x2 - x1)} \\ \\ slope \: of \: line \: = \frac{( - 6 - 6)}{(3 - ( - 3))} = - 2 \\ \\ equation \: of \: line = (y - y1) = m(x - x1) \\ \\ equation \: of \: line \: = (y - 6) = - 2(x + 3) \\ \\ equation \: of \: line \: - \\ 2x + y = 0 \: ans. \\ \\ hope \: it \: helps \: you :)

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8 0
3 years ago
Xy′ = √(1 − y2 ), y(1) = 0
tigry1 [53]

Answer:

y=sin(ln(x))

Step-by-step explanation:

First, we have to order the terms as follows and express y' as dy / dx:

x*\frac{dy}{dx} =\sqrt{(1-y^{2} )} \\\frac{x}{dx}=\frac{dy}\sqrt{(1-y^{2} )}}\\\frac{dx}{x}=\frac{dy}{\sqrt{(1-y^{2} )} }

Then, we have to integrate

\int{\frac{dx}{x}=\int{\frac{dy}{\sqrt{(1-y^{2} )} }

with this solution after integration:

ln(x)+C1=arcsin(y)+C2

Then, we have to reorder

arcsin(y)=ln(x)+C

and applied Sin function on both sides

sin(arcsin(y))=sin(ln(x)+C)\\y=sin(ln(x)+C)

To define the value of C, we use the known point y(1)=0 and replace in the equation

y=sin(ln(x)+C)\\0=sin(ln(1)+C)\\0=sin(0+C)\\0=sin(C)\\C=arcsin(0)\\C=0

The function that proves that differential equation is

y=sin(ln(x))

6 0
3 years ago
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