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3 years ago

Find the solution of this system of equations. Separate the x- and y-values with a comma. x = 8 + y and x - 11y = -12

Mathematics

1 answer:

DiKsa [7]3 years ago

3 0

The answer is:
(10, 2)

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2. Victor Larson had fixed costs totaling $2,805.60 last year, not

Mashutka [201]

The depreciation of the car is $12,600.

The cost of the car per mile is $0.28

<h3>What is the depreciation of the car?</h3>

Depreciation is the decline in the value of an asset as a result of wear and tear.

Depreciation = cost of the asset - value of the asset now

$24,890 - $12,290 = $12600

Cost per mile = total cost / total mile

($2,805.60 + $1,870.40) / 16700 = $0.28

To learn more about depreciation, please check: brainly.com/question/25552427

5 0

2 years ago

Can anyone help me with this?

Iteru [2.4K]

Look at the attached picture ⤴

Hope it will help u ..

3 0

3 years ago

6. Find LCM (10,14,63).

Katen [24]

Answer:

630 is the LCM

Step-by-step explanation:

You have to list all the multiples of each number till you find the lowest same value one which in this case it's 630.

Multiples of 10:

10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250, 260, 270, 280, 290, 300, 310, 320, 330, 340, 350, 360, 370, 380, 390, 400, 410, 420, 430, 440, 450, 460, 470, 480, 490, 500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600, 610, 620, 630, 640, 650

Multiples of 14:

14, 28, 42, 56, 70, 84, 98, 112, 126, 140, 154, 168, 182, 196, 210, 224, 238, 252, 266, 280, 294, 308, 322, 336, 350, 364, 378, 392, 406, 420, 434, 448, 462, 476, 490, 504, 518, 532, 546, 560, 574, 588, 602, 616, 630, 644, 658

Multiples of 63:

63, 126, 189, 252, 315, 378, 441, 504, 567, 630, 693, 756

3 0

3 years ago

Mr Reid needs 5 1/2 yards of fabric to make a costume. He already has 2 1/4 yards. How many yards of fabric does he need?

KiRa [710]

He needs 3 1/4 more yards of fabric because 5.5 - 2.25 = 3.25

8 0

3 years ago

Factor completely 2x^3y^4-8x^2y^3+6xy^2

Maru [420]

Answer:

2 x y^2 (x y - 1) (x y - 3)

Step-by-step explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2(x^2y^2 -4xy+3)

then lets factor the inside

what terms multiply together to give us +3 and add to -4

-3* -1 = 3 -3+-1 =-4

2 x y^2 (x y - 1) (x y - 3)

6 0

3 years ago