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Dominik [7]
2 years ago
11

Reduce these fractions to the simplest form: 21/42= *

Mathematics
1 answer:
timurjin [86]2 years ago
3 0

Answer:

1/2

Step-by-step explanation:

21 divided by 42 is 1/2

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It has two terms.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
4. Name the first five terms of the arithmetic sequence. a1 = -35, d=4​
eduard

Answer:

Step-by-step explanation:

We first have to write the equation for the sequence, then finding the first five terms will be easy. Follow the formatting:

a_n=a_1+d(n-1) and we are given enough info to fill in:

a_n=-35+4(n-1) and

a_n=-35+4n-4 and

a_n=-39+4n or in linear format:

a_n=4n-39 where n is the position of the number in the sequence. We already know the first term is -35.

The second term:

a_2=4(2)-39 so

a_2=8-39 and

a_2=-31

The third term:

a_3=4(3)-39 and

a_3=12-39 so

a_3=-27 and we could go on like this forever, but the nice thing about this is when we know the difference all we have to do is add it to each number to get to the next number.

That means that the fourth term will be -27 + 4 which is -23.

The fifth term then will be -23 + 4 which is -19. You can check yourself by filling in a 5 for n in the equation and solving:

a_5=4(5)-39 and

a_5=20-39 so

a_5=-19

7 0
2 years ago
Example 2: Combining Use of the Multiplication and Addition Rules
bulgar [2K]

Answer:

The probability of getting 6's on both cubes is \frac{1}{36}.

The probability that the total score is at least 11 is \frac{1}{12}.

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is \frac{1}{6}

Probability of getting 6 on blue cube is \frac{1}{6}

Thus, the probability of getting 6's on both cubes is:

P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}

Hence, the probability of getting 6's on both cubes is \frac{1}{36}.

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}

Hence, the probability that the total score is at least 11 is \frac{1}{12}.

3 0
3 years ago
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