it would be 40000000 because there there are 7 zeroes and then you and then you multiply the two twos together and then put it in the front.
Answer:
Hey there!
3/4= 0.75
1/5=0.2
3/10=0.3
1/7=0.14
Thus, 1/7 is the smallest fraction.
Hope this helps :)
Answer:
It's the last choice:
2x + y - 1 = 0.
Step-by-step explanation:
x - 2y - 3 = 0
Convert to slope-intercept form in order to find the slope:
-2y = -x + 3
y = 1/2x - 3/2
So the slope is 1/2. The slope of a line perpendicular to this is -1 / 1/2 = -2.
Using the point-slope form to find the required equation:
y - y1 = m(x - x1)
x = 4 and y = -7 so we have:
y + 7 = -2(x - 4)
y + 7 = -2x + 8
2x + y - 1 = 0 is the answer.
Answer:
I could be wrong, but I think it's x=12
Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649