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alukav5142 [94]
2 years ago
15

Solve the inequality 4(k − 5) + 12k ≥ −4

Mathematics
2 answers:
Dominik [7]2 years ago
8 0
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
k
≥
1
k
≥
1
Interval Notation:
[
1
,
∞
)
[
1
,
∞
)
IgorC [24]2 years ago
5 0

Answer:

k ≥ 1

Step-by-step explanation:

Step 1: Write inequality

4(k - 5) + 12k ≥ -4

Step 2: Solve for <em>k</em>

  1. Distribute 4: 4k - 20 + 12k ≥ -4
  2. Combine like terms: 16k - 20 ≥ -4
  3. Add 20 to both sides: 16k ≥ 16
  4. Divide 16 on both sides: k ≥ 1
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This maximization linear programming problem is not in "standard" form. It has mixed constraints, some involving ≤ inequalities
stellarik [79]

Answer: See Annex

z (max)  = 190

x = 10

y = 20

Step-by-step explanation:

z = 5*x  +  7*y     to maximize

Subject to:

x + y ≤ 30

2*x + y ≤50

2*x - y ≥ 0

x≥=  y ≥0

5 0
3 years ago
A machine can stamp 75 caps per minute. At this rate how long will it take to stamp 3000?
Leya [2.2K]
<h2>Answer:</h2><h2>40 minutes</h2>

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
A + 6 + 3a + 5a2 + 2a + a2 + 1
Alexxandr [17]

Answer:

6a2 + 6a + 7

Step-by-step explanation:

5 0
3 years ago
9. If y = 30 when x = 7, find x when y = 12.​
Marianna [84]
I have my work at the bottom but to explain you have to divide 30/12, and I got 2.5. That means 30 is 2.5 times bigger than 12. Because we have to find x, we have to divide 7/2.5, to find what is 2.5 times smaller than 7. That’s 2.8. So, x= 2.8

6 0
2 years ago
Find the number of real number solutions for the equation. x^2+5x+7=0
koban [17]

Given a quadratic equation ax^2+bx+c=0, we define the discriminant as

\Delta = b^2-4ac

The number of real solutions of the equation depend on the sign of \Delta:

  • If \Delta>0 the equation has two solutions
  • If \Delta=0 the equation has one double solution
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In this case, we have

\Delta = 25-28=-3

And so this equation has no real solutions.

7 0
2 years ago
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