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Rudik [331]
3 years ago
13

Find each angle and arc measure Arc ST Arc RS Arc SRT

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

Answer:

Step-by-step explanation:

arc ST is 122° , it's the same as that inner angle

arc RT ( not asked for, but needed ) is 180 °

then arc RS is  360 -180-122= RS

58= RS

Then SRT is a racing version of cars from Chrysler / Dodge  :0  or also for this problem it's  180+58 =238°

:)

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Alan, david and shari are running for president of their high school. There were a total of 1,000 votes cast for president. Davi
vekshin1

Answer:

Alan received 350 votes

Step-by-step explanation:

David received 250 votes

Shari received  400 votes

1,000 - 250=750

750 - 400 = 350

7 0
3 years ago
1/4 + 2/3. Can anybody help me solve this?
weqwewe [10]

Answer:

11/12

Step-by-step explanation:

Multiply 1/4 times 3/3 and 2/3 times 4/4. That gives you 3/12 + 8/12. Add that together and you get 11/12

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3 years ago
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NemiM [27]
40% should be the answer
7 0
2 years ago
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Evaluate the line integral ?Cx2zds, where C is the line segment from (0,5,2) to (2,7,8).
Leno4ka [110]
Parameterize C by

\mathbf r(t)=(x(t),y(t),z(t))=(1-t)(0,5,2)+t(2,7,8)=(2t,5+2t,2+6t)
\implies\mathrm ds=\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt=\sqrt{44}\,\mathrm dt

So the line integral is equivalent to

\displaystyle\int_Cx^2z\,\mathrm ds=\sqrt{44}\int_{t=0}^{t=1}(2t)^2(2+6t)\,\mathrm dt=\frac{52\sqrt{11}}3
5 0
4 years ago
A football player kicks a ball with an initial upward velocity of 47 ft./s. The initial height of the ball is 3 feet. The functi
Rashid [163]

Answer: 3 seconds

We are given the following function:

h(t)=-16{t}^{2}+V.t+h(o)    (1)

Where:

t is the time the ball is in the air

V=47ft/s the initial upward velocity

h(o)=3ft the initial height of the ball

h(t) is the final height of the ball. If no one catches it, this will be <u>zero</u>

So, equation (1) changes to:

-16{t}^{2}+V.t+h(o)=0    (2)

Substituting the known values:

-16{t}^{2}+(47ft/s).t+3ft=0    (3)

This is a quadratic equation in the form a{t}^{2}+b.t+c=0. In order to find t we can use the quadratic formula for the roots:

t=\frac{-b\pm\sqrt{-4ac}}{2a}    (4)

Where a=-16, b=47 and  c=3

Substituting this values in (4):

t=\frac{-47\pm\sqrt{-4(-16)(3)}}{2(-16)}    (5)

t=\frac{-47\pm\sqrt{2401}}{-32}    (6)

t=\frac{-47\pm\49}{-32}    (7)

For t1:

t1=\frac{-47+49}{-32}=-0.0625 s      (8)>>>> This result does not work for us because is negative

For t2:

t2=\frac{-47-49}{-32}=3 s   (9)>>>This is the result

Therefore:

<h2> If no one catches the ball, it will be 3 s in the air</h2>
6 0
3 years ago
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