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2 years ago

Find each angle and arc measure Arc ST Arc RS Arc SRT

Mathematics

1 answer:

Yuki888 [10]2 years ago

5 0

Answer:

Step-by-step explanation:

arc ST is 122° , it's the same as that inner angle

arc RT ( not asked for, but needed ) is 180 °

then arc RS is 360 -180-122= RS

58= RS

Then SRT is a racing version of cars from Chrysler / Dodge :0 or also for this problem it's 180+58 =238°

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faust18 [17]

Answer:

1.one solution

2.no solution

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Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

If a triangle is 12 inches high and has a 20 inch long hypotenuse then how wide is it?

Ber [7]

Answer:

The triangle should be 16 inches wide.

Step-by-step explanation:

$\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2$

What we know:

One of the legs measures 12 inches.

The hypotenuse is 20 inches.

We need to solve for b. Solving for a while b is 12 would also be acceptable.

$12^2 + b^2 = 20^2 \text { OR } a^2 +12^2=20^2$

We will use the first equation.

$12^2 + b^2 = 20^2\\12 * 12 = 144\\20 * 20 = 400\\\\\boxed {144 + b^2 = 400}$

$\text {Subtraction property of equality: }\\144-144+ b^2 = 400-144\\\boxed {b^2 = 256}\\\\\text {Take the square root of 256: }\\\sqrt{256}=\sqrt{b^2} \boxed {16 = b}$

The triangle should be 16 inches wide.

3 0

3 years ago

He unit circle has a radius of 1 unit and is centered at the origin. It is dilated so that it passes through the point (4, 0).

Advocard [28]

We know that

if the dilated circle passes through the point (4, 0)
so
the new radius is the distance from the origin to point (4,0)
d=√[(4-0)²+0²]-----> d=√16------> d=4 units

the new radius is 4 units
original radius is 1 units

[new radius]=[scale]*[original radius]
scale=new radius/original radius-----> scale=4/1-----> 4

the answer is
the scale factor of dilation is 4

5 0

3 years ago

PLZZZZZZZ HELPPPP

dolphi86 [110]

Answer:

The correct option is 1.

Step-by-step explanation:

It is given than the area of the triangle ABC is 46cm².

Area of a triangle is

$A=\frac{1}{2}\times base\times height$