Answer:
Step-by-step explanation:
She has 290 cents.
Nickels: 6x+1
Quarters: x
Dimes: 4x
Now that we've converted it algebraically, we can add them
6x+1 + x + 4x = 11x+1 = 290
11x = 289
x = 289/11
let me know if incorrect, i will fix
Answer:
24
Step-by-step explanation:
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24÷2=12
12+7=19
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Can’t help if there’s no figure
Answer:
3888pi cm^3 or 12214.5122372 cm^3
Step-by-step explanation:
To being, let's list out what we know
The volume of a sphere is
V = 4/3(pir^3)
But this is only half of a sphere, so the volume of it should be
V =2/3(pir^3)
With the diameter of the shape being
d = 36
We will first need to find the radius to use the formula above
r = d / 2
= 36 / 2
= 18
Now, let's start plugging in values
V = 2/3(pi18^3)
= 2/3 ( 5832pi)
= 3888pi or 12214.5122372
If you have any questions, please let me know in the comments section of this answer! If you could mark this answer as the brainliest, I would greatly appreciate it! :D
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
