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Angelina_Jolie [31]
3 years ago
12

Find two integers whose sum is -13 and product is 42

Mathematics
2 answers:
marta [7]3 years ago
8 0

Answer:

they are -6 and -7

Step-by-step explanation:

inn [45]3 years ago
8 0

Answer:

x+y=-13......i

xy=42........ii

from ii, x =42/y...iii

put iii in i

42/y +y =-13

(42+y²)/y=-13

42+y²=-13y

y²+13y+42=0

y²+6y+7y+42=0

(y²+6y)+(7y+42)=0

y(y+6)+7(y+6)=0

(y+7)(y+6)

y= -7 or -6

if y=-7,

x-7=-13

x=-6

if y=-6

x-6=-13

x=-7

x= -7,-6

y=-6,-7

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Solve for x in the equation x2-8x+41=0
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Answer:

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Step-by-step explanation:

Here we have to use the quadratic formula.

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Now plug in the given values in the above formula, we get

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Simplifying the above, we get

x = \frac{8 +/- \sqrt{64 - 164} }{2}

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Now dividing by 2, we get

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Hope you will understand the concept.

Thank you.

3 0
2 years ago
Read 2 more answers
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in the right place possibly

-3q² + 3qp + 2rp - 2rq + Sq - Sp

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Answer:

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4 0
2 years ago
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