All categories

3 years ago

Find two integers whose sum is -13 and product is 42

Mathematics

2 answers:

marta [7]3 years ago

8 0

Answer:

they are -6 and -7

Step-by-step explanation:

inn [45]3 years ago

8 0

Answer:

x+y=-13......i

xy=42........ii

from ii, x =42/y...iii

put iii in i

42/y +y =-13

(42+y²)/y=-13

42+y²=-13y

y²+13y+42=0

y²+6y+7y+42=0

(y²+6y)+(7y+42)=0

y(y+6)+7(y+6)=0

(y+7)(y+6)

y= -7 or -6

if y=-7,

x-7=-13

x=-6

if y=-6

x-6=-13

x=-7

x= -7,-6

y=-6,-7

You might be interested in

A regular polygon is inscribed in a circle of radius 11 cm. Calculate the perimeter of the polygon to the nearest tenth if the p

Oduvanchick [21]

I believe the answer is 176cm cause if the radius is 11 the diameter is 22 so I hope this helps!

7 0

3 years ago

What is the value of x?

Lerok [7]

Answer:

3√2

Step-by-step explanation:

The hypotenuse of an isosceles right triangle is √2 times the side length.

x = 3√2

_____

All these triangles are similar, so the ratio of hypotenuse to leg is the same for all.

hypotenuse/leg = x/3 = (3+3)/x

x² = 3·6 = 3²·2 . . . . cross multiply (identify square factors)

x = 3√2 . . . . . take the square root

7 0

3 years ago

11. Given: TQ bisects ZRTP, QS || PT RT = 30. Find QP, RS and QS

yaroslaw [1]

QP=24 cm

RS=11.25 cm

QS=18.75 cm

Explanation:

Given that TQ bisects <RTP

$therefore$ (1)

consider ΔRQS and ΔRPT

QS||PT,RP and RT are transversals

(alternate angles)(2)

comparing (1) and (2)

and triangle SQT is isocelus

Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)

Therefore <RQS=<RPT(corresponding angles)

<RSQ=<RTP(corresponding angles)

therefore by AA criterion for similarity

ΔRQS~ΔRPT

According to the property of similar triangles

$RQ/RP=RS/RT=QS/PT$ $9/RP=X/30=QS/50\\9/RP=X/30=(30-X)/50\\X/30=(30-X)/50\\50X=30(30-X)\\50X=900-30X\\50X+30X=900\\80X=900\\X=900/80=11.25\\RS=11.25 cm\\QS=30-X=30-11.25\\QS=18.75 cm\\9/RP=X/30\\9/RP=11.25/30\\9*30/11.25=RP\\RP=24 cm$

3 0

3 years ago

Find the quotient 3,085 +3

dem82 [27]

3,088 is the answer

5 0

3 years ago

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s heigh

Nataly_w [17]

Answer D). 9 ft is correct

Height of the ball at a horizontal distance of 10 feet is 9 ft

Step-by-step explanation:

A ball is thrown and it follows a parabolic path. At each horizontal distance (x) the following equation models the ball’s height (y).

Y(x) = $-0.02x^{2} +0.8x+3$

Question asked is " What will be height (Y) of the ball when X=10 ft "

Simply putting value of X in given equation

we get,

Y(x) = $-0.02x^{2} +0.8x+3$

Y(x) = $-0.02(10)^{2} +0.8(10)+3$

Y(x) = $-0.02(100)} +8+3$

Y(x) = $-2 +8+3$

Y(x) = $9$

Therefore, Height of the ball at a horizontal distance of 10 feet is 9 ft

Answer D. 9 ft is correct

6 0

3 years ago