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saul85 [17]
3 years ago
12

What is the quotient?

Mathematics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

-1.58208955224

Step-by-step explanation:

DO THE MATH

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Question12....................................
tatyana61 [14]

Answer:

u = ± 4

Step-by-step explanation:

Given

u² = 16 ( take the square root of both sides )

u = ± \sqrt{16} = ± 4

u = - 4, u = 4

5 0
3 years ago
The equation below describes a parabola. If a is positive, which way does the
Rzqust [24]
B. Up

Because a positive ‘a’ value will make the parabola open upwards, and because the power is 2 (even) both sides will open up in a ‘U’ shape
8 0
2 years ago
Read 2 more answers
What is the solution for the equation 6x − 8 = 4x? x = . (Input whole number only). (5 points) Blank 1:
vfiekz [6]

Answer:

4

Step-by-step explanation:

Step 1:

6x - 8 = 4x        Equation

Step 2:

6x = 4x + 8        Add 8 on both sides

Step 3:

2x = 8     Subtract 4x on both sides

Step 4:

x = 8 ÷ 2      Divide

Answer:

x = 4

Hope This Helps :)

6 0
3 years ago
conner deposited $84 into his checking account. if his new Balance is $451, what was his balance before the deposit
prisoha [69]
His balance was originally $367 
3 0
3 years ago
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
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