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tatyana61 [14]
3 years ago
8

Solve solving systems using substitution.

Mathematics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

your answer would be D

Step-by-step explanation:

Substitute the x= 3y-1 in place of the x in the second equation

Subtract Like terms

Add 3 to both sides

Divide by 3(the coeffcient of y)

Answer is 5

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Hi, Could anyone help me with my homework
tatiyna

Answer:

\hookrightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

solving steps:

\rightarrow \sf (x + 4)^6

\bold{rewrite \ the \ following}

\rightarrow \sf (x + 4)^2   (x + 4)^2   (x + 4)^2

\bold {formula \ used : \sf  (x+a)^2 = (x^2 + 2xa + a^2)}

\rightarrow \sf (x^2 + 8x+16)    (x^2 + 8x+16)    (x^2 + 8x+16)

\bold{simplify \ by  \ removing \ parenthesis}

\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)

\bold{basic \ addition \ of \ integers }

\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)

\bold{remove \ parenthesis}

\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)

\bold {final \ answer:}

\rightarrow \sf  x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096

8 0
2 years ago
What is 1 4/5 + 1 1/5??
Rudik [331]
1\dfrac{4}{5}+1\dfrac{1}{5}=(1+1)+\left(\dfrac{4}{5}+\dfrac{1}{5}\right)=2+\dfrac{1+4}{5}=2+\dfrac{5}{5}=2+1=3
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slega [8]

Answer:

The y intercept for the equation is (0,-7)

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Answer:

1 quart = .947 L

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So you should use 2.841 L to dissolve the powder

3 0
3 years ago
Help me on this algebra homework
Makovka662 [10]
X = 
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