Answer:
The forecast for November is 235 if August's forecast was 145.
Step-by-step explanation:
The formula for calculating forecast using exponential smoothing is:
Where Ft = New month forecast
Ft-1 = Previous month forecast
At-1 = Previous month actual value
α = smoothing constant
We are given F₈ = 145 (forecast for August), A₈ = 200 (Actual Value for August), α = 2, and we need to compute the forecast for November. So, We will first calculate the forecast for September then October and then November, step-by-step.
So, forecast for September is:
F₉ = F₈ + α (A₈ - F₈)
= 145 + 2*(200-145)
= 145 + 2*55
F₉ = 255
Then, forecast for October is:
F₁₀ = F₉ + α (A₉ - F₉)
= 255 + 2*(220-255)
= 255 + 2*(-35)
F₁₀ = 185
The forecast for November is:
F₁₁ = F₁₀ + α (A₁₀ - F₁₀)
= 185 + 2*(210 - 185)
F₁₁ = 235
R=6 & s=1/4
Just plug that in to the equation.
6+1/4 +14(1/4)
6.25 +3.5
9.75 or 39/4
Answer: oop
Step-by-step explanation:
Let X = smaller number
Let Y = larger number
Sum of numbers is 130 ==> X + Y = 130 ==> Y = 130 - X
4 times the smaller subtracted from the larger is 10 ==>
Y - 4*X = 10
Substitute the value for Y in to the 2nd equation
(130 - X) - 4*X = 10
130 - 5*X = 10
-5*X = -120
X = 24
Y = 130 - 24 = 106
Check: 24 + 106 = 130
106 - 4*24 = 106 - 96 = 10
Answer:
y = 
x - 5
Step-by-step explanation:
Given f(0) = - 5 and f(4) = - 3 , then we have the coordinate points
(0, - 5) and (4, - 3)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = 
with (x₁, y₁ ) = (0, - 5) and (x₂, y₂ ) = (4, - 3)
m = 
= 
=
The line crosses the y- axis at (0, - 5) ⇒ c = - 5
y = f(x) = x - 5 ← equation of line
The answer is y=5 because -.5x-4=2 and 2 +3=5
