If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
32 rooms
Step-by-step explanation:
You have to divide
In the b section on this piece of paper, we can see, that this would practically be a pie graph, or if you would want to call it a graph in general. As the question stated, we see how we would want to find the perimeter of the figure. So this, sense this would only be 1/4 of the figure, we would then do 4(in) x's 4 and from this, your perimeter would give you 16(in).
To find the range of data, you first order the data least to greatest:
7, 12, 15
Then you subtract the smallest number from the largest:
15-7=8
The range is 8.
Answer:
xx=-0.8
Step-by-step explanation:
not sure if this is right because the 12xx is kind of strange
12xx+16-1=0
12xx+15=0
12xx=-15
12/12xx=12/-15
xx=-.8
