1 minutes equals 1 where 1 hour equals 60 minutes. From this, an hour is 60 times greater than a minute
Answer:
- Average age of the employees in 2003 = 57.216
- Average age of the employees in 2009 = 59.184
Step-by-step explanation:
We are given the function A(s) as;
A(s) = 0.328*s + 50 where s = number of years since 1981; that is,
s = 0 for 1981 and s = 9 for 1990
A(s) = the average age of an employee
- Now, the average age of the employees in 2003, A(22) = 0.328*22 + 50
Here s = 22 because 2003 - 1981 = 22 years
Therefore, average age of the employees in 2003 = 7.216 + 50 = 57.216 .
- Average age of the employees in 2009, A(28) = 0.328*28 + 50
Here, s = 28 because 2009 - 1981 = 28 years
Therefore, average age of the employees in 2009 = 9.184 + 50 = 59.184 .
All really need to do is pick one number. so, we will go with 6 and 87.
6 times 12 is 72 then you subtract that from $87.
That would be 15
To double check, you can use another one. 9 and 123.
9 times 12 is 108. subtract that from 123 and you get 15.
Your answer is B) $15
Hope I helped :)
Answer: y= 7x-48
Step-by-step explanation: