N(CuSO₄)=135/{63.5+32.1+4*16.0}=0.846 mol
n(CuSO₄*5H₂O)=135/{63.5+32.1+4*16.0+5*(2*1.0*+16.0)}=0.541 mol
n(H₃PO₄)=135/{3*1.0+31.0+4*16.0}=1.378 mol
n(BaCl₂)=135/{137.3+2*35.5}=0.648 mol
Answer:
The answer to your question is: Flask X
Explanation:
Data
Flask X Flask B
Molar mass 30 g 60 g
mass 1.2g 1.2 g
Pressure 1 atm 0.5 atm
Formula PV = nRT
In the formula, we can notice that the number of moles (n)
is directly proportional to the pressure.
Then, let's calculate the number of moles
flask X flask Y
30 g --------------- 1 mol 60 g -------------- 1 mol
1.2 g ---------------- x 1.2 g ------------- x
x = (1.2 x 1) / 30 x = (1.2 x 1) / 60
x = 0.04 mol x = 0.02 mol
From the results, we conclude that the flask with the gas of molar mass 30g is the flask with pressure of 1 atm, because the higher the number of moles, the higher the pressure.
Answer:
I. dissolving more solute in an unsaturated solution
Explanation:
A saturated solution is the solution which contains maximum concentration of solute dissolved in solvent.
However, if the solution is being provided with energy (heating) , it will dissolve more heat and the solution that cannot even dissolve more solute after heating is super saturated solution.
<u>Both saturated and supersaturated solutions have maximum of their capacity to dissolve the solute and hence further energy requires energy and these processes are non-spontaneous.</u>
<u>An unsaturated solution can dissolve more solute easily and thus is a spontaneous process.</u>
<u></u>
The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below
calculate the moles of C4H10 used = mass/molar mass
moles = 4.86g/58 g/mol =0.0838 moles
write a balanced equation for reaction
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
by use of mole ratio between C4H10 to H2O which is 2:10 the moles of
H20= 0.0838 x10/2 = 0.419 moles of H2O
mass = moles x molar mass
=0.419 molx 18 g/mol = 7.542 grams of water is formed
