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telo118 [61]
4 years ago
8

What is the common name of H2O

Chemistry
2 answers:
schepotkina [342]4 years ago
8 0
H2O is also know as water
Mrac [35]4 years ago
8 0
H2O is also known as water
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Balance the chemical equation <br> FeS2+O2——&gt;Fe2O3+SO2
Vikki [24]

Answer:

that is the answer

Explanation:

the atoms in each side of the equation must be equal.

6 0
3 years ago
Write true or false next to each of these statements.
Serggg [28]

Answer:

a) False ( all metals are not magnetic for ex - gold is not magnetic )

b) false ( Diamond is a solid non metal still it shine)

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3 0
3 years ago
HELPPPP PLEASEEEE
Rama09 [41]

1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.

<h3>How to calculate molarity?</h3>

The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;

no of moles = molarity × volume

According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.

no of moles = 8.20 × 0.125

no of moles = 1.025moles

Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.

Learn more about number of moles at: brainly.com/question/14919968

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6 0
2 years ago
Where is air pressure greater exophere or trophere
PtichkaEL [24]
Exit here is the answer or this question
5 0
4 years ago
AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin
svet-max [94.6K]

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

P1V1=P2V2

Therefore

P1=\frac{P2V2}{V1}\\\\P2=\frac{98.2*1}{5.5}

P2=17.854 kPa

For more information on Pressure visit

brainly.com/question/25688500

7 0
3 years ago
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