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AleksandrR [38]
3 years ago
6

Which element has a greater electronegativity? fluorine (9) or radium (88)

Chemistry
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer:

Fluorine

General Formulas and Concepts:

<u>Chemistry</u>

  • Reading a Periodic Table
  • Periodic Trends
  • Electronegativity - the tendency for an element to attract an electron to itself
  • Z-effective and Coulomb's Law, Forces of Attraction

Explanation:

The Periodic Trend for Electronegativity is up and to the right of the Periodic Table.

Fluorine is Element 9 and has 9 protons. Radium is Element 88 and has 88 protons. Therefore, Radium has a bigger Zeff than Flourine.

However, since Radium is in Period 7 while Fluorine is in Period 2, Radium has more core e⁻ than Fluorine does. This will create a much larger shielding effect, causing Radium's outermost e⁻ to have less FOA between them. Fluorine, since it has less core e⁻, the FOA between the nucleus and outershell e⁻ will be much stronger.

Therefore, Fluorine would attract an electron more than Radium, thus bringing us to the conclusion that Fluorine has a higher electronegativity.

Lapatulllka [165]3 years ago
6 0

Answer:

Fluorine

Explanation:

Electronegativity increases as you go from left to right across the periodic table and decreases as you go from top to bottom of the periodic table.

Fluorine is in period 3, group 17

Radium is in period 7, group 2

Radium is in period 7 and we know that electronegativity decreases as you move from top to bottom.

Explanation: As you move from top to bottom, you are in higher energy level, which means that your distance from the nucleus is further away.

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A solution has a pH of 2.5. what is the H+
romanna [79]

<u>Answer: </u>The concentration of H^+ in the solution is 3.16\times 10^{-3}M

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution.

pH=-\log [H^+]      .....(1)

We are given:

pH of solution = 2.5

Putting values in equation 1, we get:

2.5=-\log [H^+]

[H^+]=10^{-2.5}

[H^+]=3.16\times 10^{-3}M

Hence, the concentration of H^+ in the solution is 3.16\times 10^{-3}M

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3 years ago
Is camphor heated a physical/chemical change​
DedPeter [7]

Answer:

when it is heated it changes to vapor, which is a physical change

Explanation:

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4 years ago
An elephant has a mass of 156,000 kg and a volume of 6 KL. Find the elephant's density.
bixtya [17]

Answer:

26,000 KL/kg will be the density of the Elephant.

4 0
3 years ago
At 14,000 ft elevation the air pressure drops to 0.59 atm. Assume you take a 1L sample of air at this altitude and compare it to
Ray Of Light [21]

Answer:

There are 0.1125 g of O₂ less in 1 L of air at 14,000 ft than in 1 L of air at sea level.

Explanation:

To solve this problem we use the ideal gas law:

PV=nRT

Where P is pressure (in atm), V is volume (in L), n is the number of moles, T is temperature (in K), and R is a constant (0.082 atm·L·mol⁻¹·K⁻¹)

Now we calculate the number of moles of air in 1 L at sea level (this means with P=1atm):

1 atm * 1 L = n₁ * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 K

n₁=0.04092 moles

Now we calculate n₂, the number of moles of air in L at an 14,000 ft elevation, this means with P = 0.59 atm:

0.59 atm * 1 L = n₂ * 0.082 atm·L·mol⁻¹·K⁻¹ * 298 K

n₂=0.02414 moles

In order to calculate the difference in O₂, we substract n₂ from n₁:

0.04092 mol - 0.02414 mol = 0.01678 mol

Keep in mind that these 0.01678 moles are of air, which means that we have to look up in literature the content of O₂ in air (20.95%), and then use the molecular weight to calculate the grams of O₂ in 20.95% of 0.01678 moles:

0.01678mol*\frac{20.95}{100} *32\frac{g}{mol} =0.1125 gO_{2}

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Which of the following molecular compounds does NOT need the usage of prefix for the first element
Mrrafil [7]

Answer:

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Explanation:

that's my answer

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