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AleksandrR [38]
2 years ago
6

Which element has a greater electronegativity? fluorine (9) or radium (88)

Chemistry
2 answers:
emmainna [20.7K]2 years ago
7 0

Answer:

Fluorine

General Formulas and Concepts:

<u>Chemistry</u>

  • Reading a Periodic Table
  • Periodic Trends
  • Electronegativity - the tendency for an element to attract an electron to itself
  • Z-effective and Coulomb's Law, Forces of Attraction

Explanation:

The Periodic Trend for Electronegativity is up and to the right of the Periodic Table.

Fluorine is Element 9 and has 9 protons. Radium is Element 88 and has 88 protons. Therefore, Radium has a bigger Zeff than Flourine.

However, since Radium is in Period 7 while Fluorine is in Period 2, Radium has more core e⁻ than Fluorine does. This will create a much larger shielding effect, causing Radium's outermost e⁻ to have less FOA between them. Fluorine, since it has less core e⁻, the FOA between the nucleus and outershell e⁻ will be much stronger.

Therefore, Fluorine would attract an electron more than Radium, thus bringing us to the conclusion that Fluorine has a higher electronegativity.

Lapatulllka [165]2 years ago
6 0

Answer:

Fluorine

Explanation:

Electronegativity increases as you go from left to right across the periodic table and decreases as you go from top to bottom of the periodic table.

Fluorine is in period 3, group 17

Radium is in period 7, group 2

Radium is in period 7 and we know that electronegativity decreases as you move from top to bottom.

Explanation: As you move from top to bottom, you are in higher energy level, which means that your distance from the nucleus is further away.

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An intravenous infusion is to contain 15 mEq of potassium ion and 20 mEq of sodium ion in 500 mL of 5% dextrose injection. Using
Studentka2010 [4]

Answer:

To supply the required ions it is necessary to inject 5,6mL of 6g/30mL solution and 131,1 mL of 0,9% solution.

Explanation:

1mEq of sodium are 59mg of NaCl and 1mEq of potassium are 75mg KCl

in intravenous infusion 15 mEq of K are:

15x75mg KCl = 1,125g of KCl

And 20 mEq of Na are:

20x59mg NaCl = 1,18g of NaCl

To supply the potassium ion it is necessary to inject:

1,125g of KCl×\frac{30mL}{6g} =<em> 5,6mL  of 6g/30mL solution</em>

And, to supply the sodium ion it is necessary to inject:

1,18g of NaCl×\frac{100mL}{0,9g} = <em>131,1 mL of 0,9% solution</em>

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6 0
3 years ago
The stock concentration of NaOH is 0.5M. 0.5M = 0.500mol/1.0L.
valentinak56 [21]

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Explanation: in 200mL , 0.1mole

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density NaOH = 1g/mL so if 4g in 200 mL,  4mL , 196 mL water

5 0
2 years ago
What is the main exception in the atomic radius? Explain.
yarga [219]

Answer:

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hope this helps!

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Explanation:

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Independent would be the amount of sugar given and the dependent would be the amount of cavities

Scientists have control groups so they can have evidence to show the difference between that one and the experimental ones.

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