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AleksandrR [38]
2 years ago
6

Which element has a greater electronegativity? fluorine (9) or radium (88)

Chemistry
2 answers:
emmainna [20.7K]2 years ago
7 0

Answer:

Fluorine

General Formulas and Concepts:

<u>Chemistry</u>

  • Reading a Periodic Table
  • Periodic Trends
  • Electronegativity - the tendency for an element to attract an electron to itself
  • Z-effective and Coulomb's Law, Forces of Attraction

Explanation:

The Periodic Trend for Electronegativity is up and to the right of the Periodic Table.

Fluorine is Element 9 and has 9 protons. Radium is Element 88 and has 88 protons. Therefore, Radium has a bigger Zeff than Flourine.

However, since Radium is in Period 7 while Fluorine is in Period 2, Radium has more core e⁻ than Fluorine does. This will create a much larger shielding effect, causing Radium's outermost e⁻ to have less FOA between them. Fluorine, since it has less core e⁻, the FOA between the nucleus and outershell e⁻ will be much stronger.

Therefore, Fluorine would attract an electron more than Radium, thus bringing us to the conclusion that Fluorine has a higher electronegativity.

Lapatulllka [165]2 years ago
6 0

Answer:

Fluorine

Explanation:

Electronegativity increases as you go from left to right across the periodic table and decreases as you go from top to bottom of the periodic table.

Fluorine is in period 3, group 17

Radium is in period 7, group 2

Radium is in period 7 and we know that electronegativity decreases as you move from top to bottom.

Explanation: As you move from top to bottom, you are in higher energy level, which means that your distance from the nucleus is further away.

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The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect
DedPeter [7]

Answer: The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect of adding more bromine gas to the reaction chamber?

More fluorine gas will be produced.

More bromine gas will be produced.

More bromine monofluoride gas will be produced.

Less bromine monofluoride gas will be produced.

I think it is more bromine monofluoride will be produce

Explanation:

8 0
2 years ago
In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2. 4NH3 + 5O2 &gt; 4NO + 6H2O a. Which reactant is the limi
cluponka [151]

Answer:

2.61 g of NO will be formed

The limiting reagent is the O₂

Explanation:

The reaction is:

4NH₃  +  5O₂  →  4NO  +  6H₂O

We convert the mass of the reactants to moles:

3.25g / 17 g/mol = 0.191 moles of NH₃

3.50g / 32 g/mol =0.109 moles of O₂

Let's determine the limiting reactant by stoichiometry:

4 moles of ammonia react with 5 moles of oxygen

Then, 0.191 moles of ammonia will react with (0.191 . 5) / 4 = 0.238 moles of oxygen. We only have 0.109 moles of O₂ and we need 0.238, so as the oxygen is not enough, this is the limiting reagent

Ratio with NO is 5:4

5 moles of oxygen produce 4 moles of NO

0.109 moles will produce (0.109 . 4)/ 5 = 0.0872 moles of NO

We convert the moles to mass, to get the answer

0.0872 mol . 30g / 1 mol = 2.61 g

7 0
3 years ago
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