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3 years ago

How do I do question C?! Mass to moles

Chemistry

1 answer:

Andrei [34K]3 years ago

5 0

N(CuSO₄)=135/{63.5+32.1+4*16.0}=0.846 mol

n(CuSO₄*5H₂O)=135/{63.5+32.1+4*16.0+5*(2*1.0*+16.0)}=0.541 mol

n(H₃PO₄)=135/{3*1.0+31.0+4*16.0}=1.378 mol

n(BaCl₂)=135/{137.3+2*35.5}=0.648 mol

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A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use

LekaFEV [45]

The empirical formula of this compound is $H_2SO_4$

Given the following data:

Percentage of H = 2.00%

Percentage of S = 32.7%

Percentage of O = 65.3%

Scientific data:

Molar mass of hydrogen (H) = 1.0 g/mol.

Molar mass of sulfur (S) = 32 g/mol.

Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

Mass of hydrogen (H) = 2.00 grams

Mass of sulfur (S) = 32.7 grams

Mass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

For hydrogen (H):

$Number\;of\;moles = \frac{2.00}{1}$

Number of moles = 2.0 moles

For sulfur (S):

$Number\;of\;moles = \frac{32.7}{32}$

Number of moles = 1.0 moles

For oxygen (O):

$Number\;of\;moles = \frac{65.3}{16}$

Number of moles = 4.0 moles

Empirical formula = $H_2SO_4$

3 0

2 years ago

According to cell theory _____.

bulgar [2K]

Answer:

Every single living thing are comprised of cells. Cells are the fundamental units of structure and capacity in living things. New cells are delivered from existing cells.

4 0

4 years ago

How many grams are in 1.46 mol K2O?

CaHeK987 [17]

Answer:

94.196 grams

Explanation:

6 0

3 years ago

Read 2 more answers

Based on formal charges, draw the most preferred Lewis structure for the chlorate ion, ClO3−. To add lone pairs, click the butto

vova2212 [387]

Answer:

The structure is shown in the diagram.

Explanation:

Lewis structure : In order to draw Lewis structure we will calculate the total number of valence electrons in the molecule.

The valence electrons from Cl : 7

The valence electrons from O = 3 X 6 = 18

Charge negative so more electrons = 2

total electrons = 7 + 18 +2 = 27

Now we will distribute the electrons on each atom and in between atoms as shown in the diagram.

8 0

3 years ago

Read 2 more answers

If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the

DIA [1.3K]

Answer:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Fe: 4 moles
O₂: 3 moles
Fe₂O3: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?

$moles of Fe =\frac{4. moles of Fe*4.7 moles of O_{2}}{3 moles of O_{2} }$

moles of O₂= 6.27

But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.

So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?

$moles of Fe_{2}O_{3}=\frac{5.4 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}$

moles of Fe₂O₃= 2.7 moles

Then:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

4 0

3 years ago