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larisa86 [58]
3 years ago
12

How do I do question C?! Mass to moles

Chemistry
1 answer:
Andrei [34K]3 years ago
5 0
N(CuSO₄)=135/{63.5+32.1+4*16.0}=0.846 mol

n(CuSO₄*5H₂O)=135/{63.5+32.1+4*16.0+5*(2*1.0*+16.0)}=0.541 mol

n(H₃PO₄)=135/{3*1.0+31.0+4*16.0}=1.378 mol

n(BaCl₂)=135/{137.3+2*35.5}=0.648 mol
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Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

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The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

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