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larisa86 [58]
3 years ago
12

How do I do question C?! Mass to moles

Chemistry
1 answer:
Andrei [34K]3 years ago
5 0
N(CuSO₄)=135/{63.5+32.1+4*16.0}=0.846 mol

n(CuSO₄*5H₂O)=135/{63.5+32.1+4*16.0+5*(2*1.0*+16.0)}=0.541 mol

n(H₃PO₄)=135/{3*1.0+31.0+4*16.0}=1.378 mol

n(BaCl₂)=135/{137.3+2*35.5}=0.648 mol
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ODIO POD
miss Akunina [59]

Answer:

\boxed{\text{40 mol Al}}

Explanation:

            Al₂O₃ ⟶ 2Al + 3O₂

n/mol:     20

\text{Moles of Al} = \text{20 mol Al$_{2}$O$_{3}$}\times \dfrac{\text{2 mol Al}}{\text{1 mol Al$_{2}$O$_{3}$}}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}

8 0
3 years ago
1. If the atomic number of an element is 6 and its mass number is 14, how many neutrons are contained in the nucleus?
Iteru [2.4K]

You can find the neutrons by subtracting the mass by the atomic number. 14-6=8 neutrons

8 0
3 years ago
In a solution with a pH of 3.0, the color of
Alinara [238K]

Answer:

A) litmus is red

Explanation:

To answer this question, it can be helpful to have the color charts. Litmus, phenolphthalein and methyl orange are ways to test the pH of a substance.

<u>Litmus paper</u>

Litmus can tell you if a substance is an acid or a base. You need to put the substance on both red litmus and blue litmus paper.

pH < 7: both papers are red. 3.0 is less than 7.

pH = 7: none of them change color

pH > 7: both papers are blue

<u>Phenolphthalein</u>

When this indicator is added to a substance, the result is either colorless or pink.

0 < pH ≤ 7: colorless. The color is not red or blue for pH 3.0.

pH > 7: pink

<u>Methyl orange</u>

0 < pH < 4: red. The color is not yellow if the pH is 3.0.

4 ≤ pH < 5: orange

pH ≥ 5: yellow

5 0
3 years ago
Blood is red. Is this an intensive or extensive physical property?
Anastaziya [24]

Answer: Intensive physical property

Explanation: Color is an intensive physical property since intensive properties are properties that stay the same no matter the amount of the substance is present. Blood is still red whether or not you have 2 liters of it or 4 liters.

8 0
3 years ago
Dilute 0.407M &amp; 2.56L solution to 7.005L. CF?
Alenkinab [10]

Answer:

C₂ = 0.149 M

Explanation:

Given data:

Initial concentration = 0.407 M

Initial volume = 2.56 L

Final volume = 7.005 L

Final concentration = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Initial concentration

V₁ = Initial volume

C₂ = Final concentration

V₂ =Final volume

Now we will put the values.

0.407 M × 2.56 L =  C₂ × 7.005 L

1.042 =  C₂ × 7.005 L

C₂ = 1.042 M.L / 7.005 L

C₂ = 0.149 M

5 0
3 years ago
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