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Oksanka [162]
3 years ago
11

A student simplifies the given expression. Which statement BEST describes the error in the student's work? 12 + 24 ÷ 6(4) 36 ÷ 2

4 36/24 = 3/2
A) The student added before multiplying.
B) The student multiplied before dividing.
C) The student divided before multiplying.
D) The student simplified the answer incorrectly.
E) The student added incorrectly.
Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
A. The student added before multiplying.
If they had multiplied 6 and 4 first, the next step would have been too divide. But since they added first, they got 36/24 or 3/2 when the answer should be 13.
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What value does the 2 in the number 0.826?
Deffense [45]

Answer:

.02

Step-by-step explanation:

2 is in "Hundredths' place in .826

So, the number is multiplied with 1/100 or .01

=> 2 x 1/100

=> 2/100

=> .02

=> 2 x .01

=> .02

The value of 2 in .826 is .02

6 0
3 years ago
How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and
omeli [17]

Step-by-step explanation:

x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\     (given)

Let us consider :

x_{1} = t_{1} + 1

x_{2} = t_{2}

x_{3} = t_{3}

x_{4}  = t_{4}

x_{5} = t_{5}

Now, by substituting the above considerations in the above equation, we get:

t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\

t_{1}  + t_{2} + t_{3} + t_{4} + t_{5} = 20\\

where,

t_{i} \geq 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = _{r}^{n + r}\textrm{C}

                                                      = _{4}^{24}\textrm{C}

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Answer :

no. of solutions for the eqn 10626

4 0
3 years ago
5 tons of rocks cost $8,200.00. What is the price per pound?<br><br>2000 ibs =1 ton
natima [27]
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8 0
3 years ago
Each week, Rosario drives to an ice-skating rink that is 60 miles away. The round-trip takes 2.75 hours. If he averages 55 miles
vazorg [7]

Answer:

The answer to your question is x = 4d/t - S1

Step-by-step explanation:

Data

total time = t = 2.75 hours

Initial speed = S1 = 55 mi/h

Final speed = x

distance = d = 60 mi

Formula

speed = distance / time

Average speed = (Initial speed + final speed)/2  or

                          = (S1 + x)/2

Substitution

                             (S1 + x)/2 = 2(d) / t

Solve for x

                             x = (2d/t)2 - S1

Simplification and result

                              x = 4d/t - S1

3 0
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4 + 2x = 7
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