Answer:
1. acceleration value
2. 20 m
3a. when you throwing somethinb upward
3b. when a thing reach maximum height after throwing upward
4. (entire only) velocity = diaplacement/ time = 0/91 = 0
speed = distance/time = 200/91 = 2.2 m/s
5. (40-20)/4 = 5 m/s²
6. displacement using phytagoras get 50 m
velocity = displacement/time = 50/(6+4) = 5 m/s
7. 0, it turn back to the base
8. speed = distance/time = (240*2)/(4+6) = 48 km/h
9. s = (4+14)*3/2 =27 m
