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3 years ago

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The Sun is a type G2 star. Type G stars (from G0 to G9) have a range of temperatures from 5200 to 5900. What is the range of log

(T) for G stars

1 answer:

otez555 [7]3 years ago

8 0

Answer:

Explanation:

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the answer B

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3 years ago

Two basketball players are essentially equal in all respects. (They are the same height, they jump with the same initial velocit

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What do crystal of table salt look like?

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4 years ago

Calculate the depth in the ocean at which the

nirvana33 [79]

Explanation:

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P = Patm + ρgh

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3 years ago

Consider a uniformly volume‑charged sphere of radius R and charge Q . What is the electric potential on the surface of the spher

VARVARA [1.3K]

To solve this problem we will start by applying the given load ratio, and we will rely on the two types of distances given. Later we will use Gauss's law and through its integrals, in which it is equivalent to the potential we will obtain its value in the center of the sphere. Since it is uniformly charged we have to,

$\frac{Q'}{Q} = \frac{4\pi r^3}{4\pi R^3}$

$Q' = \frac{r^3}{R^3} Q$

By Gauss Law

$\phi = E \cdot 4\pi r^2$

Here, E is the electric Field and is equal to

$E = \frac{Q'}{\epsilon_0}$

For $\epsilon_0$ being the Permeability constant at free space

Replacing with the previous value we have,

$\phi = \frac{Qr^3}{\epsilon_0 R^3}$

Then the value of the electric field is,

$E = \frac{QR}{4\pi \epsilon_0 R^3}$

Now potential

$V = \int_0^R E\cdot dr'$

$V = - \frac{QR^2}{8\pi \epsilon_0 R^3}$

$V = -\frac{Q}{8 \pi \epsilon_0 R}$

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3 years ago