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Verdich [7]
3 years ago
8

Which best describes the required locus? all points in a plane equidistant from two given points in the plane.

Mathematics
2 answers:
zavuch27 [327]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

The line that is a perpendicular bisector of the segment connecting the two points.

Leona [35]3 years ago
3 0

Answer:

C. The line that is a perpendicular bisector of the segment connecting the two points

Step-by-step explanation:

I took the test and got it right.

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If<br> R = (5+T)P/3<br> then what is p?
Illusion [34]

Answer:

Step-by-step explanation:

R = (5+T)P/3

3R = (5+T)P

3R/ (5+T) = P

P =    \frac{3R}{(5+T) }

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3 years ago
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Katena32 [7]

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PLEASE HELP ME IN MATH IM CONFUSED
Butoxors [25]

Answer:

the second choice is correct

Step-by-step explanation:

The equation of a line in slope- intercept form is

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y = \frac{3}{4} x - 9 is in this form

with slope m = \frac{3}{4}

• Parallel lines have equal slopes, hence

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4 0
3 years ago
I don't even know how to figure this out. I don't have a formula for this
yuradex [85]

Answer:

\sin\theta=\dfrac{15}{17}

?=15

Step-by-step explanation:

Use the trigonometry formula

\cos^2\theta+\sin^2\theta=1

You are given that

\cos \theta=\dfrac{8}{17}

Substitute into the first formula

\left(\dfrac{8}{17}\right)^2+\sin^2\theta=1\\ \\\dfrac{64}{289}+\sin^2\theta=1\\ \\\sin^2\theta=1-\dfrac{64}{289}=\dfrac{289-64}{289}=\dfrac{225}{289}\\ \\\sin \theta=\pm \dfrac{15}{17}

Angle \theta is acute angle, then the sine of this angle is positive and

\sin\theta=\dfrac{15}{17}

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3 years ago
RADIO TELESCOPES The cross section of a large radio telescope is a parabola. The equation that describes the cross section is y=
Minchanka [31]

Answer:

I am sorry

Step-by-step explanation:

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3 years ago
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