Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
6x + 15
anything 2 ask please pm me
Answer:
$8.96
Step-by-step explanation:
To find the total amount, multiply the percentage of the tip (20%) as 0.20 with 7.47
(7.47×0.20=1.494)
Add $1.49 to $7.47
(1.49+7.47=8.96)
And there is your total amount with a 20% tip!
$8.96
The second one I beileve is the answer to your question
Answer:
D. x=4
Step-by-step explanation:
We can solve this with the Pythagorean Theorem for the right triangle that we can see (which is half of the triangle).
The bottom length is 3 and the hypotenuse is 5.
The Pythagorean Theorem is a²+b²=c².
We can plug this in:
3²+x²=5²
9+x²=25
x²=16
x=4