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2 years ago

What is bc divided by 2?(Algebra)

Mathematics

2 answers:

liubo4ka [24]2 years ago

7 0

Wdym what is bc divided by 2

klasskru [66]2 years ago

3 0

What are you talking about ?

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Help Me Pls I Will Give Brainliest

mylen [45]

Answer:

Hi!

My name is Euijin :D and the answer is:

600$

Step-by-step explanation:

I Divided 12 and 0.02 and got 600

5 0

2 years ago

What number two numbers when multiplied equal 24 but when added equal -4

madam [21]

Since it says when Added they are a negative and when multiplied they are positive, we know our two numbers are negative.
think of all multiples of 24
6 and 4
8 and 3
12 and 2
24 and 1
however, none of our choices here would be correct.

5 0

2 years ago

Tommy has 6 more than 3 times the amount of money in his bank account than Judy. Judy has $7500 more than a number in her accoun

balu736 [363]

Answer: Judy: n+7500

Tommy: 3(n+7500)+6

Step-by-step explanation:

4 0

2 years ago

Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

2 years ago

Part 2 of Question please help me <br> and thank you for your help

san4es73 [151]

1 tick represents 8 units

4 0

1 year ago