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eimsori [14]
3 years ago
9

In quadrilateral QRST, Angle R S T measures (5x+15)°. Angle TQR measures (4x+3)°. Circle P is inscribed with quadrilateral Q R S

T. What is the measure of angle RST? 15° 75° 105° 165°
Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0

Answer:

105degrees

Step-by-step explanation:

Using the theorems that states that the sum of the opposite side of the quadrilateral is 180degrees, hence;

<RST + <TQR = 180

5x+15 + 4x+ 3 = 180

9x + 18 = 180

9x = 180 - 18

9x = 162

x = 162/9

x = 18

Since <RST = 5x+15

<RST = 5(18) + 15

<RST = 90 + 15

<RST = 105degrees

Hence the measure of <RST is 105degrees

Georgia [21]3 years ago
4 0

Answer:

c

Step-by-step explanation:

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Given: Quadrilaterals ABCD ~ EFGH , with measure of angle A = 47 degrees, measure of angle B = 39 degrees, and measure of angle
kaheart [24]

Answer:

The answer is below

Step-by-step explanation:

Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.

Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.

In quadrilateral ABCD:

∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)

Substituting:

47 + 39 + 112 + ∠D = 360

∠D + 198 = 360

∠D = 360 - 198

∠D = 162°

The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:

∠A = ∠E = 47°

∠B = ∠F = 39°

∠C = ∠G = 112°

∠D = ∠H = 162°

3 0
2 years ago
Brainliest if correct. pls help. improper answer will lead to automatic report. will not report if wrong. 25+pts
RideAnS [48]

Answer:

x = 1.56

Step-by-step explanation:

so what you have to do is isolate the variable by dividing each side by factors that don't contain the variable.

8 0
3 years ago
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The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui
mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

s(t) = -16t^2+v_0t+s_0

Where,

s_0 = initial height of the object,

v_0 = initial velocity of the object,

Here,

s_0=400\text{ feet}

v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

\implies -16t^2+35t+400=0

t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}

t=\frac{-35\pm \sqrt{1225+25600}}{-32}

\implies t\approx -4.02\text{ or }t\approx 6.21

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0
3 years ago
\dfrac {15}k
Monica [59]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
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Given that 1 kilogram weighs approximately 22 pounds, rewrite 10 pounds as an equivalent number of kilograms
yaroslaw [1]

Answer:

0.4545 kgs.

Step-by-step explanation:

Given that 1 kg weighs approximately 22 pounds.

i.e. 1kg= 22 lbs.

We can use this to convert lbs into kg.

22 lbs = 1 kg

Hence 1 lb = 1/22 = 0.04545 kg

Now to find out the equivalent weight for 10lbs,

we have conversion factor as 1 lb= 0.04545 kg

Hence 10 lbs = 10(0.04545) = 0.4545 kgs

Hence 10 pounds written in equivalent kgs would be0.4545 kgs.

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