<img src="https://tex.z-dn.net/?f=%20tan%20%5Calpha%20%20%5Ctimes%20sin%20%5Calpha%20%20%3D%20" id="TexFormula1" title=" tan \al

All categories

Korolek [52]

3 years ago

pha \times sin \alpha = " alt=" tan \alpha \times sin \alpha = " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Tan(α) x sin(α)

Using tan(t) = sin(t) / cos(t), transform the expression:

sin(α) / cos(α) x sin(α)

Calculate the product:

sin(α)² / cos(α)

Final answer:

= sin(α)² / cos(α)

You might be interested in

Ray delivered 3/8 of the newspapers on his route in the first hour and 4/5 of the rest in the second hour what fraction of the n

Temka [501]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

Let the total number of Newspapers be x

Number of newspapers delivered in first hour of his route= $\frac{3}{8}$ of x

Total number of newspapers delivered in first hour= $\frac{3}{8}$ x

Number of newspapers left= x- $\frac{3x}{8}$

Number of newspapers left= $\frac{8x-3x}{8}$

Number of newspapers left= $\frac{5x}{8}$

Number of newspapers delivered in second hour=4/5 of $\frac{5x}{8}$

Number of newspapers delivered in second hour= $\frac{x}{2}$

Fraction of newspapers delivered in second hour is= $\frac{1}{2}$

Hence, the correct answer is $\frac{1}{2}$

8 0

3 years ago

M is the MIDPOINT OF FG. FG = 26 AND GM = (3X - 2)

vova2212 [387]

It is given in the question that

M is the MIDPOINT OF FG.

$FG = 26 \ AND \ GM = (3X - 2)$

Since M is the midpoint of FG, therefore GM is half of FG. That is

$3X-2 = \frac{1}{2} (26)$

$3X-2 =13
\\
3X = 15
\\
X =5$

Therefore

$GM = 3(5) -2 = 13$

And FM is 13 too .

3 0

3 years ago

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$