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julia-pushkina [17]
4 years ago
9

This has to be solved using the greatest common factor, grouping, or difference of squares. Thanks in advance!

Mathematics
1 answer:
kobusy [5.1K]4 years ago
4 0
A² - a²x²- a²+ x²

= x² - a²x²

= x² (1 - a²)

= x²( 1 - a) (1 + a)

Answer:  x²( 1 - a) (1 + a)
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4 years ago
The graph of the equation x ^ 2 + y ^ 2 - 16x + 6y + 14 = 0 is a circle. An equivalent form of this equation is (x - 8) ^ 2 + (y
storchak [24]

Answer:

author link

ghanami

Ace

2.9K answers

12.1M people helped

hello :

note :

an equation of the circle Center at the w(a,b) and ridus : r is :

(x-a)² +(y-b)² = r²  

in this exercice : x²+y²-16x+6y+53=0

(x²-16x) +( y²+6y ) +53 = 0

(x² -2(8)x +8² -  8²) +(y² +2(3)x -3²+3² ) +53=0

(x² -2(8)x +8²) -  8² +(y² +2(3)x +3²)-3²  +53=0

(x-8)² +( y+3)² = 20

the center is :  w(8,-3) and ridus : r  = √20

Still stuck? Get 1-on-1 help from an expert tutor now.

Step-by-step explanation:

3 0
3 years ago
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