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julia-pushkina [17]
3 years ago
9

This has to be solved using the greatest common factor, grouping, or difference of squares. Thanks in advance!

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0
A² - a²x²- a²+ x²

= x² - a²x²

= x² (1 - a²)

= x²( 1 - a) (1 + a)

Answer:  x²( 1 - a) (1 + a)
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46% printers are defective = 106 printers defective
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Find the next two terms of the sequence. 2,6,10,14,...
dimaraw [331]
The pattern is add 4

So the answer is C
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Tyler has 45% of his pay check remaining. What fraction of his pay check does he have remaining?
Andreyy89

Answer:

If he has 45% of his cheak remaining we already have the remaining so we just to turn it into a fraction

First we put it over 100

<u>45</u>

100

Then we reduce it to the lowest terms

which would be

9/20

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Is there a difference in the amount of airborne bacteria between carpeted and uncarpeted rooms? In an experiment, seven rooms we
Annette [7]

Answer:

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Step-by-step explanation:

A. There are outliers in these data, so we can't rely on the two-sample t test.

There are no outliers, as the seven rooms for both sample have similar size and function.

B. This test is unreliable because the populations we're sampling from are heavily skewed.

We don't know if the populations are heavily skewed, but this effect should be appeased by the sampling.

C. There isn't much evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

Correct conclusion, as the P-value is surely greater than the significance level (usually 0.10 at most).

D. There is fairly strong evidence to support a conclusion that the presence of carpet is associated with an increase or decrease in the mean bacterial concentration of air.

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4 0
3 years ago
The length of a rectangle is 6 yd more than twice the width x. The area is 416 yd2. Find the dimensions of the rectangle.
kati45 [8]

Answer:

13 yds * 32 yds

Step-by-step explanation:

A=area, l=length, w=width

A=w*l

l=6+2w

A=w*(6+2w)

A=6w+2w^2

416=6w+2w^2

416/2=(6w+2w^2)/2

208=3w+w^2

208-208=3w+w^2-208

w^2+3w-208=0

w^2+16w-13w-208=0

w(w+16)-13(w+16)=0

(w-13)(w+16)=0 ==> w+16=0 ==> w=-16, w can't be negative.

w-13=0

<u>w=13</u>

l=6+2w

l=6+2(13)

l=6+26

<u>l=32</u>

Dimensions: 13 * 32

8 0
1 year ago
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